Answer:
The volume of the mercury sample at 273 K is 49.818 mL
Explanation:
Step 1: Data given
Volume at 293 K = 50.00 mL
The coefficient of volume expansion of mercury is 182.0 * 10^-6/K
Step 2: Calculate the new volume
ΔV = β*Vi*ΔT
⇒ with ΔV = the change in volume
⇒ with β = The coefficient of volume expansion of mercury is 182.0 * 10^-6/K
⇒ with Vi =the initial volume = 50.00 mL
⇒ with ΔT = the change in temperature = 20 K
ΔV = 182.0 * 10^-6/K * 50 *20
ΔV = 0.182 L
This means the volume change is -0.182 L
ΔV = V2 - V1
V2 = ΔV - V1
V2 = 50.00 mL -0.182= 49.818 mL
The volume of the mercury sample at 273 K is 49.818 mL
