At the complete combustion of butane the carbon dioxide and water are formed.
2C₄H₁₀ + 13O₂ = 8CO₂ + 10H₂O
C₄H₁₀ ⇒ 4CO₂, 5H₂O ⇒ 13O ⇒ 6.5O₂
we use integer coefficients: 8CO₂, 10H₂O, 13O₂
Answer:
Metals at the top
nonmetals at the bottom
metalloids in the middle
Don't quote me, i could be wrong. i think this is the correct order.
Explanation:
Recycling Isn’t Always Cost Effective.
High Up Front Cost
Needs More Global Buy-In.
Recycled Products Are Often of Lesser Quality.
Recycling Sites Are Commonly Unsafe.
Depression in freezing point (Δ
![T_{f}](https://tex.z-dn.net/?f=%20T_%7Bf%7D%20)
) =
![K_{f}](https://tex.z-dn.net/?f=%20K_%7Bf%7D%20)
×m×i,
where,
![K_{f}](https://tex.z-dn.net/?f=%20K_%7Bf%7D%20)
= cryoscopic constant =
![1.86^{0} C/m](https://tex.z-dn.net/?f=%201.86%5E%7B0%7D%20C%2Fm)
,
m= molality of solution = 0.0085 m
i = van't Hoff factor = 2 (For
![NaNO_{3}](https://tex.z-dn.net/?f=%20NaNO_%7B3%7D%20)
)
Thus, (Δ
![T_{f}](https://tex.z-dn.net/?f=%20T_%7Bf%7D%20)
) = 1.86 X 0.0085 X 2 =
![0.03162^{0}C](https://tex.z-dn.net/?f=%200.03162%5E%7B0%7DC%20)
Now, (Δ
![T_{f}](https://tex.z-dn.net/?f=%20T_%7Bf%7D%20)
) =
![T^{0}](https://tex.z-dn.net/?f=%20T%5E%7B0%7D%20)
- T
Here, T = freezing point of solution
![T^{0}](https://tex.z-dn.net/?f=%20T%5E%7B0%7D%20)
= freezing point of solvent =
![0^{0}C](https://tex.z-dn.net/?f=%200%5E%7B0%7DC%20)
Thus, T =
![T^{0}](https://tex.z-dn.net/?f=%20T%5E%7B0%7D%20)
- (Δ
![T_{f}](https://tex.z-dn.net/?f=%20T_%7Bf%7D%20)
) = -
1) 0.89% m/v = 0.89 grams of NaCl / 100 ml of solution
=> 8.9 grams of NaCl in 1000 ml of solution = 8.9 grams of NaCl in 1 liter of solution
2) Molarity = M = number of moles of solute / liters of solution
=> calculate the number of moles of 8.9 grams of NaCl
3) molar mass of NaCl = 23.0 g /mol + 35.5 g/mol = 58.5 g / mol
4) number of moles of NaCl = mass / molar mass = 8.9 g / 58.5 g / mol = 0.152 mol
5) M = 0.152 mol NaCl / 1 liter solution = 0.152 M
Answer: 0.152 M