Question

As his socks tumbled in the dryer, they became charged. If a small piece of lint with a charge of +1.25 E -19 C is attracted to the socks by a force of 3.0 E -9 N, what is the magnitude of the electric field at this location?

Answer 1

Answer:

$2.4\cdot 10^{10}N$

Explanation:

When an electric charge is immersed in an electric field, it experiences a force given by the equation

$F=qE$

where

q is the charge

E is the magnitude of the electric field

In this problem, we have:

$q=+1.25\cdot 10^{-19}C$ is the charge on the small piece of lint

$F=3.0\cdot 10^{-9}N$ is the force experienced by the  charge

Therefore, we can find the magnitude of the electric field by re-arranging the equation and solving for E:

$E=\frac{F}{q}=\frac{3.0\cdot 10^{-9}}{1.25\cdot 10^{-19}}=2.4\cdot 10^{10}N$