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3 years ago

What affect does doubling the net force have on the acceleration of the object (when

Physics

2 answers:

Triss [41]3 years ago

8 0

<h3>Answer: The acceleration doubles</h3>

===========================================================

Explanation:

Consider a mass of 10 kg, so m = 10

Let's say we apply a net force of 20 newtons, so F = 20

The acceleration 'a' is...

F = ma

20 = 10a

20/10 = a

2 = a

a = 2

The acceleration is 2 m/s^2. Every second, the velocity increases by 10 m/s.

---------------

Now let's double the net force on the object

F = 20 goes to F = 40

m = 10 stays the same

F = ma

40 = 10a

10a = 40

a = 40/10

a = 4

The acceleration has also doubled since earlier it was a = 2, but now it's a = 4.

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In summary, if you double the net force applied to the object, then the acceleration doubles as well.

Alborosie3 years ago

7 0

Acceleration is directly proportional to the net force on an object, and inversely proportional to its mass.

So if an object's mass stays the same while the net force on it doubles, then <em>its acceleration will also double</em>.

We don't know anything about the "trials". This sounds like it might be a follow-up to a lab experiment that was performed when we weren't there.

We also don't know anything about "question 1".

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3 years ago

Why does it hurt more when you fall on concrete than on grass?

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Answer:

Smaller forces are easier on your legs and you prefer to land on soft grass. Momentum/impulse explanation: Whether you land on concrete or soft grass, your change in momentum will be identical. A hard surface that brings you to a stop in 0.01 s requires a much larger force of 15,000 N.

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3 years ago

Read 2 more answers

a train engineer drives a train 235 km north along a straight track . then he drives the train back south 126 km . finally , he

yuradex [85]

let here North direction is along +Y and South direction is along -Y

similarly East direction is towards +X and west direction is towards -X

now it is given that

first it moves 235 km north

$d_1 = 235 \hat j$

then it moves back 126 km south

$d_2 = - 126 \hat j$

then again he moves north

$d_3 = 45 \hat j$

now the total displacement is given as

$d = d_1 + d_2 + d_3$

$d = 235 - 126 + 45 = 154 km$

so final displacement of train is 154 km North

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4 years ago

During a 400-m race, a runner crosses the 100 m mark with a velocity of 12 m/s. What would be her final position if she maintain

Cerrena [4.2K]

Answer:

Explanation:

Given that

Total race distance is 400m

Her initial velocity was 0m/s²

At the 100m mark, after she has travelled 100m, her final velocity was v=12m/s²

Using equation of motion

Let determine her constant acceleration

v²=u²+2as

12²=0²+2×a×100

144=0+200a

144=200a

a=144/200

a=0.72m/s²

Then we want to know her position after another 10second

So total time is 10+12=22seconds

Then, using equation of motion

Let determine his postion

S=ut+½at²

S=0•t+½×0.72×22²

S=0+174.24

S=174.24 m

Her position will be 174.24m

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4 years ago

Read 2 more answers

An airline employee tosses two suitcases in rapid succession with a horizontal velocity of 7.2 ft/s onto a 50-lb baggage carrier

zalisa [80]

Answer:

m₁ = 70 lb

Explanation:

Here we will use the law of conservation of momentum:

m₁u₁ + m₂u₂ + m₃u₃ = m₁v₁ + m₂v₂ + m₃v₃

where,

m₁ = mass of first suitcase = ?

m₂ = mass of second suitcase = 30 lb

m₃ = mass of baggage carrier = 50 lb

u₁ = initial speed of first suitcase = 7.2 ft/s

u₂ = initial speed of second suitcase = 7.2 ft/s

u₃ = initial speed of baggage carrier = 0 ft/s

v₁ = Final speed of first suitcase = 4.8 ft/s

v₂ = Final speed of second suitcase = 4.8 ft/s

v₃ = Final speed of baggage carrier = 4.8 ft/s

because after collision all three will have same speed

Therefore,

(m₁)(7.2 ft/s) + (30 lb)(7.2 ft/s) + (50 lb)(0 ft/s) = (m₁)(4.8 ft/s) + (30 lb)(4.8 ft/s) + (50 lb)(4.8 ft/s)

(m₁)(7.2 ft/s) + (216 lb ft/s) + (0 lb ft/s) = (m₁)(4.8 ft/s) + (144 lb ft/s) + (240 lb ft/s)

(m₁)(7.2 ft/s) - (m₁)(4.8 ft/s) = 168 lb ft/s

m₁ = (168 lb ft/s)/(2.4 ft/s)

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3 years ago