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Serhud [2]
3 years ago
13

Let's say you have two tuning forks which are supposed to produce the same frequency, 512 Hz. One is of good quality, but the ot

her is cheaply made and vibrates at 510 Hz. If you bonk them both how many beats per second will you hear
Physics
1 answer:
solong [7]3 years ago
7 0

Answer:

= 2 beats per seconds

Explanation:

  • From |f -f'| = modulus of the difference between the frequency given.
  • f = 510Hz and f' = 512Hz
  • Difference between the frequency will give us the number of beat per seconds.
  • i.e 2 beats per seconds

These also shows how to get the period of the tuning forks.

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Explanation:

The electrostatic force between two charged particle is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

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Substituting, we find the electrostatic force between the two ions:

F=(8.99\cdot 10^9) \frac{(1.6\cdot 10^{-19})(-1.6\cdot 10^{-19})}{(282\cdot 10^{-12})^2}=-2.9\cdot 10^{-10} N

where the negative sign simply means that the force is attractive, since the two ions have opposite charge.

Learn more about electrostatic force:

brainly.com/question/8960054

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