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Serhud [2]
3 years ago
13

Let's say you have two tuning forks which are supposed to produce the same frequency, 512 Hz. One is of good quality, but the ot

her is cheaply made and vibrates at 510 Hz. If you bonk them both how many beats per second will you hear
Physics
1 answer:
solong [7]3 years ago
7 0

Answer:

= 2 beats per seconds

Explanation:

  • From |f -f'| = modulus of the difference between the frequency given.
  • f = 510Hz and f' = 512Hz
  • Difference between the frequency will give us the number of beat per seconds.
  • i.e 2 beats per seconds

These also shows how to get the period of the tuning forks.

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An object of mass 8kg moved around the circle of radius 4m. with a constant speed of 15m/s.
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Answer:

a. Angular velocity = 0.267rad/s.

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Explanation:

<u>Given the following data;</u>

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Substituting into the equation, we have;

Angular velocity = 4/15

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3 years ago
A resistor, inductor, and a battery are arranged in a circuit. The circuit has an inductance of L = 1 H and a resistance of 1.4
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Answer:

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\tau =\frac{L}{R}

Therefore, the time needed for the current to reach a fraction f = 0.6(60%) of its maximum value is:

\tau =\frac{1}{1.4\times 10^{3}} =7.142857143 \times 10^{-4} \approx7.14 \times 10^{-4}s

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