N = normal force by the surface of incline on the box resting on it
m = mass of the box resting on the incline surface = 30 kg
g = acceleration due to gravity acting on the box = 9.8 m/s²
θ = angle of the incline with the horizontal surface = 15⁰
from the force diagram , force equation perpendicular to incline surface is given as
N = m g Cosθ
inserting the values in the above equation
N = (30 kg) (9.8 m/s²) Cos15
N = 284 newton
To solve this problem we will apply the concepts related to the double slit-experiment. Under this concept we understand the relationship between the minimum angle, depending on the order of the fringes, the wavelength and the distance between slits. Therefore we have the following relation,
Here,
m = Order of the fringes
D = Distance between slits
= Wavelength
Replacing with our values we have,
Through the relationship between distances then we have that the basic amplification distance is given by the relationship between the distance of the slit L and the angle, then
Thus the width of the central maximum is
Therefore the widht is 0.466m
I am not sure on the rest but the answer to question 4 is volts. sorry i couldn’t be of more help!