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andreyandreev [35.5K]
3 years ago
6

Isotopes of the same element always have the same

Physics
2 answers:
lord [1]3 years ago
6 0
Z number (atomic number)
xxMikexx [17]3 years ago
4 0
Please please lord thank you
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guajiro [1.7K]
Higher the pressure the air would spread apart causing the paper to move to the other side. So higher pressure causes the papers to move farther apart.
4 0
3 years ago
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Describe and explain the potential energy changes that occur during the formation of a covalent bond
Yanka [14]
<span>when two hydrogen atoms approach each other the potential energy of the combination becomes lower and lower until it reaches a minimum value of -436 kl/mol at a distance of 75 pm</span>
8 0
4 years ago
A sphere of radius 6cm is moulded into a thin cylindrical wire of length 32cm. Calculate the radius of the
suter [353]

Answer:

4/3 pi R^3 = pi r^2 L     equating volume of sphere and wire

r = (4 R^3 / 3 * L)^1/2      solving for radius of wire

r = (4 * 6^3 / 3 * 32)^1/2

r = 9^1/2 cm = 3 cm = .03 meters

5 0
2 years ago
An auto race takes place on a circular track. A car completes one lap in a time of 18.0 s, with an average tangential speed of 4
eduard

Answer:

(A) 0.3488 rad/sec

(B) 124.246 m                

Explanation:

We have given car completes one revolution in 18 sec'

So time period T= 18 sec

Tangential speed v = 43.4 m/sec

(A) Angular velocity is given by \omega =\frac{2\pi }{T}=\frac{2\times 3.14}{18}=0.3488rad/sec

(B) Tangential velocity is given v = 43.4 m /sec

We know that v=\omega r

r=\frac{v}{\omega }=\frac{43.4}{0.3488}=124.426m

4 0
3 years ago
A 6.3 μC electric charge is placed in an Electric Field with a magnitude of 5.0 x 105 charge due to the Electric Field? N/C. Wha
EastWind [94]

Answer:

F = 3.15 N

Explanation:

Given electric charge, q = 6.3 μC

The magnitude of electric field, E=5\times 10^5\ N/C

We need to find the electric force on the charge due to the electric field. The electric force is given by :

F = qE

Putting all the values,

F=6.3\times 10^{-6}\times 5\times 10^5\\\\F=3.15\ N

So, the required force on the charge is 3.15 N.

7 0
3 years ago
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