Answer:
1) 3-Ethylanisole
2) 2,3-Dibromobenzoic acid
3) 3-Fluorotoluene
Explanation:
Let us try to look at the structures of each compound one after the other as described in the question.
1) A ring with six vertices and alternating double and single bonds must refer to a benzene ring. A benzene ring having -OCH3 attached to the first vertex is called anisole. If a -CH2CH3 group is now attached at position 3, we now name the compound 3-Ethylanisole.
2) A ring with six vertices and alternating single and double bonds is a benzene ring. If the ring has -COOH attached to the first vertex, we call it benzoic acid. If bromine atoms are attached to the second and third vertices respectively, the compound is now named 2,3-Dibromobenzoic acid.
3) A ring with alternating single and double bonds is a benzene ring. If a -CH3 group is attached to the first vertex, we call the compound toluene. If a fluorine atom is now attached to position 3, the compound can now be named 3-Fluorotoluene
I'm a pharmacy dispenser which is the same thing. what's your question?
Answer:
The coefficient for PH3 is 8. Option D is correct.
Explanation:
Step 1: The unbalanced equation
P2H4(g) ⇆ PH3(g) + P4(s)
Step 2: Balancing the equation
P2H4(g) ⇆ PH3(g) + P4(s)
On the left side we have 4x H (in P2H4), on the right side we have 3x H (in PH3). To balance the amount of H on both sides, we have to multiply P2H4 on the left side by 3 and PH3 on the right by 4.
3P2H4(g
) ⇆ 4PH3(g) + P4(s)
On the left side we have 6x P (in 3P2H4) on the right side we have 8x P (4x in 4PH3 and 4x in P4). To balance the amount of P on bot hsides, we have to multiply 3P2H4 by 2 and 4PH3 also by 2. Now the equation is balanced
6P2H4(g
) ⇆ 8PH3(g) + P4(s)
The coefficient for PH3 is 8. Option D is correct.