Answer:
Explanation:P = 1 mol x 30.97 g/mol = 30.97 g N = 2 mol x 14.01 g/mol = 28.02 g. O = 4 mol x ... 5.68 g O2 f. Molecules of water produced? 2.46 g H2O ×. 1 mol H2O. 18.02 g H2O. × ... How many grams of sodium sulfate will be produced by the complete ... 2 mol BF3. 3 mol H2. = 1.65 mol BF3 required. Calculate moles H2 required:.
Answer:
Mass of ammonia = 34 g
Explanation:
Given data:
Number of molecules of ammonia = 1.204 × 10²⁴
Mass of ammonia = ?
Solution:
First of all we will calculate the number of moles.
one mole of ammonia = 6.022 × 10²³ molecules
n = 1 mole/6.022 × 10²³ molecules × 1.204 × 10²⁴ molecules
Number of moles = 2 mol
Mass of ammonia:
Number of moles = Mass / molar mass
Mass of ammonia = number of moles × molar mass
Mass of ammonia = 2 mol × 17 g/mol
Mass of ammonia = 34 g
Answer:
CStO3
Explanation:
What is need to be done here is to first divide the percentage compositions by the respective atomic masses. Atomic mass of strontium is 90, that of oxygen is 16 and that of carbon is 12.
Let’s proceed with the divisions:
St = 59/90 = 0.656
O = 33/16 = 2.0625
C = 8/12 = 0.667
Now, we divide through all by the smallest answer which is 0.656:
St = 0.656/0.656 = 1
O = 2.0625/0.656 = 3.144 = 3
C = 0.667/0.656 = 1.0167 = 1
The empirical formula is thus CStO3