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Vlad [161]
3 years ago
6

What is the molarity of a solution that contains 20.45 g of sodium chloride (NaCl) dissolved in 700.0 mL of solution?

Chemistry
1 answer:
Nostrana [21]3 years ago
6 0
Molarity is the number of moles of solute in 1 L of solution.
the mass of NaCl added - 20.45 g
number of moles of NaCl - 20.45 g / 58.5 g/mol = 0.350 mol
volume of the solution is 700.0 mL 
since molarity is the number of moles in 1000 mL 
and if 700.0 mL contains - 0.350 mol 
therefore 1000 mL contains - 0.350 mol / 700.0 x 1000 = 0.500 mol 
hence molarity of solution is 0.500 M
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3 years ago
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(b)Calculate the number of moles of CuSO4 that were in the impure sample of CuSO4(s) .
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Answer:

The questions are incomplete

Explanation:

(b) This question is incomplete. However to calculate the number of moles of CuSO₄ present in the impure sample. The formula below can be used;

number of moles = mass of CuSO₄ present in the impure sample ÷ molar mass of CuSO₄

(c) This question is also incomplete. However, to calculate the mass percentage of CuSO₄ present in the impure sample of CuSO₄, the formula below can be used.

Mass percentage of CuSO₄ =

mass of CuSO₄ present in the impure sample/mass of impure CuSO₄ × 100

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3 years ago
42.9 liters of hydrogen are collected over water at 76.0 °C and has a pressure of 294 kPa. What would the pressure (in kPa) of t
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Answer:

494.1 kPa

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (kPa)

P2 = final pressure (kPa)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

P1 = 294 kPa

P2 = ?

V1 = 42.9 liters

V2 = 22.8 liters

T1 = 76.0°C = 76 + 273 = 349K

T2 = 38.7°C = 38.7 + 273 = 311.7K

294 × 42.9/349 = P2 × 22.8/311.7

12612.6/349 = 22.8 P2/311.7

36.14 = 22.8P2/311.7

Cross multiply

36.14 × 311.7 = 22.8P2

11264.605 = 22.8P2

P2 = 11264.605 ÷ 22.8

P2 = 494.1 kPa

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