Answer:
The final temperature is 31.95° C.
Explanation:
Given that,
Initial temperature of a sample of chloroform, ![T_i=25^{\circ} C](https://tex.z-dn.net/?f=T_i%3D25%5E%7B%5Ccirc%7D%20C)
Mass of chloroform, m = 150 g
It absorbs 1 kJ of heat, Q = 10³ J
The specific heat of chloroform, c = 00.96 J/gºC
We need to find the final temperature. The heat absorbed by an object in terms of specific heat is given by :
![Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\\dfrac{Q}{mc}+T_i=T_f\\\\T_f=\dfrac{10^3}{150\times 0.96}+25\\\\=31.95^{\circ} C](https://tex.z-dn.net/?f=Q%3Dmc%5CDelta%20T%5C%5C%5C%5CQ%3Dmc%28T_f-T_i%29%5C%5C%5C%5C%5Cdfrac%7BQ%7D%7Bmc%7D%2BT_i%3DT_f%5C%5C%5C%5CT_f%3D%5Cdfrac%7B10%5E3%7D%7B150%5Ctimes%200.96%7D%2B25%5C%5C%5C%5C%3D31.95%5E%7B%5Ccirc%7D%20C)
So, the final temperature is 31.95° C.
Period are going left to right across the periodic table
Groups are going up to down on the periodic table
I think it’s d
If it’s wrong then I’m sorry
Heat capacity of aluminium = 0.900 J/g°C
While heat capacity of water = 4.186 J/g°C
Heat = heat gained by water + heat gained by aluminium
Heat gained by water = 100 × 4.186 × 30.5
= 12767.3 Joules
Heat gained by aluminium = 15 × 0.9 × 30.5
= 411.75 Joules
Heat required = 13179.05 Joules or 13.179 kJoules