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4 years ago

How to solve for b in the following equation... 53.2=30.5b^50

Mathematics

1 answer:

Margarita [4]4 years ago

7 0

Answer:

b = (53.2/30.5)^(1/50) ≈ 1.011188765

Step-by-step explanation:

Divide by the coefficient of the variable, then take the 50th root.

53.2/30.5 = b^50

(53.2/30.5)^(1/50) = b . . . . . . 50th root of both sides of the equation

You know the rule of exponents for powers of powers is ...

(a^b)^c = a^(bc)

If we want bc = 1, then we must have c = 1/b.

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The table below shows some inputs and outputs of the invertible function f etc

Snowcat [4.5K]

Answer:

$(a)\ f^{-1}(-15) = -6$

$(b)\ f^{-1}(4) + f(9)=0$

Step-by-step explanation:

Given

The attached table

$(a)\ f^{-1}(-15)$

This represents an inverse function.

So, we look into x row for its value.

i.e.

$f^{-1}(-15) = -6$

$(b)\ f^{-1}(4) + f(9)$

Just like (a)

$f^{-1}(4) = -11$ ---- by looking into the x rows

$f(9) = 11$

So:

$f^{-1}(4) + f(9)=-11 + 11$

$f^{-1}(4) + f(9)=0$

4 0

3 years ago

Rectangle ABCD is dilated by a scale factor of One-half with a center of dilation at the origin. What are the coordinates of the

MissTica

Answer:

The new coordinate of image of point B (-4, 6) will be B'(-2, 3) when a rectangle ABCD is dilated by a scale factor of One-half with a center of dilation at the origin.

Step-by-step explanation:

Considering the vertices of the rectangle ABCD

A(-8, 6)

B(-4, 6)

C(-4, 4)

D(-8, 4)

When a rectangle ABCD is dilated by a scale factor of One-half with a center of dilation at the origin, then the coordinate of image of point B can be calculated by multiplying the x and y coordinates of point B with 1/2.

i.e.

B(-4, 6) → B'(-4/2, 6/2) = B'(-2, 3)

Therefore, the new coordinate of image of point B (-4, 6) will be B'(-2, 3) when a rectangle ABCD is dilated by a scale factor of One-half with a center of dilation at the origin.

4 0

4 years ago

Read 2 more answers

Which expression gives the volume of a sphere with radius 15?

Nesterboy [21]