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victus00 [196]
3 years ago
13

. How many moles are there in 8.5x 1025 molecules of co2

Chemistry
2 answers:
bogdanovich [222]3 years ago
6 0
1 mole => 6.023 x 10^23 molecules

x => 8.5 x 10^25 molecules

x = 8.5x10^25/ 6.023 x 10^23 = 141.1 



Sergeeva-Olga [200]3 years ago
3 0

Explanation:

According to the mole concept, there are 6.022 \times 10^{23} atoms present in 1 mole of a substance.

Mathematically,    1 mole = 6.022 \times 10^{23} atoms or molecules

Therefore, calculate the number of moles of CO_{2} present in 8.5 \times 10^{25} molecules as follows.

              \frac{8.5 \times 10^{25}}{6.022 \times 10^{23}}

                 = 1.411 \times 10^{2} mol

or,              = 141.1 mol

Thus, we can conclude that there are 141.1 moles present in 8.5 \times 10^{25} molecules of CO_{2}.

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Answer:

d. To the left because Q > K_p

Explanation:

Hello,

In this case, for the given reaction:

CaCO_3(s) \rightarrow CaO(s) + CO_2(g)

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In such a way, since Kp is given we rather compute the reaction quotient at the specificed pressure of carbon dioxide as shown below:

Q=p_{CO2}=1.0

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The balanced chemical equation for the reaction between iodine gas and chlorine gas is given below.

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Step 2 : Set up ICE table

We will set up an ICE table for the above reaction

Following points are considered while drawing ICE table

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- The coefficients in balanced equation are considered while writing C values

Check attached file for ICE table

Step 3 : Set up equilibrium constant equation

The equation for equilibrium constant can be written as

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Step 4 : Solving for x

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81.9 = \frac{(2x)^{2}}{(0.437-x) (0.269-x)}

81.9 = \frac{(2x)^{2}}{x^{2} -0.706x + 0.118}

(2x)^{2} = 81.9 [ x^{2} -0.706x + 0.118]

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