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Ilya [14]
3 years ago
8

What is 114.1 kPa to atm

Chemistry
1 answer:
denis23 [38]3 years ago
4 0

Answer:

1.126 atm

Explanation:

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Substances that are likely to disassociate in water
mr_godi [17]

Answer:

sugar,dirt,spit

Explanation:

5 0
3 years ago
Balance equation Al(s)+__CuSO4(aq) = ____Al2(SO4)3(aq)+____Cu(s)
Leokris [45]
2Al +3CuSO4=Al2 (SO4)3+3Cu.

is the balanced equation.

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8 0
4 years ago
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What mass of the protein gelatin is needed to make 0.5 L of a 3 g/L gelatin solution? Show your work.
REY [17]

Answer:

m = 1.5 gram

Explanation:

Given that,

Density of protein gelatin, d = 3 g/L

The volume of protein gelatin, V = 0.5 L

We need to find the mass of the protein gelatin. The density of an object is given by :

d = m/V

Where

m is mass

m=d\times V\\\\m=3\ g/L\times 0.5\ L\\\\m=1.5\ g

So, the required mass is 1.5 gram.

6 0
2 years ago
Substances that cannot be separated and found on a periodic table
GaryK [48]

Substances that cannot be separated and found on a periodic table are elements.


4 0
3 years ago
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The standard enthalpy change for the following reaction is 873 kJ at 298 K.
Flura [38]

Answer:  - 436.5 kJ.

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation.

The given chemical reaction is,

2KCl(s)\rightarrow 2K(s)+Cl_2(g)  \Delta H_1=873kJ

Now we have to determine the value of \Delta H for the following reaction i.e,

K(s)+\frac{1}{2}Cl_2(g)\rightarrow KCl(s) \Delta H_2=?

According to the Hess’s law, if we divide the reaction by half then the \Delta H will also get halved and on reversing the reaction , the sign of enthlapy changes.

So, the value \Delta H_2 for the reaction will be:

\Delta H_2=\frac{1}{2}\times (-873kJ)

\Delta H_2=-436.5kJ

Hence, the value of \Delta H_2 for the reaction is -436.5 kJ.

8 0
3 years ago
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