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Assoli18 [71]
3 years ago
9

How many grams of KCl are needed to prepare 1.00 L of a 2.00 M solution

Chemistry
1 answer:
Andrej [43]3 years ago
8 0
Use the concentration and molar mass.

1.00 L (2.00 mol KCl/1 L)(74.6 g/ 1 mol KCl)= 149.2 grams

So, you need about 149 grams of KCl dissolved in 1 liter of water to prepare a 2.00 M solution. 
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SVP

=

1

⋅

a

t

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1

⋅

a

t

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∘

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