How many grams of KCl are needed to prepare 1.00 L of a 2.00 M solution
1 answer:
Use the concentration and molar mass.
1.00 L (2.00 mol KCl/1 L)(74.6 g/ 1 mol KCl)= 149.2 grams
So, you need about 149 grams of KCl dissolved in 1 liter of water to prepare a 2.00 M solution.
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