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3 years ago

How many grams of KCl are needed to prepare 1.00 L of a 2.00 M solution

1 answer:

8 0

Use the concentration and molar mass.

1.00 L (2.00 mol KCl/1 L)(74.6 g/ 1 mol KCl)= 149.2 grams

So, you need about 149 grams of KCl dissolved in 1 liter of water to prepare a 2.00 M solution.

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A scientist observes several metals and records the followinv data.which of the data sets represents qualitative data?A The máss

Strike441 [17]

The answers C and D are correct.

4 0

3 years ago

For the following reaction in aqueous solution, identify all those species that will be spectator ions. Select all that apply.

uranmaximum [27]

The reaction is incorrect. The correct reaction is: Na₂SO₄ + Hg(NO₃)₂ → HgSO₄ + 2NaNO₃. The options are:

A. Hg₂SO₄

B. Na₂SO₄

C. Na⁺

D. NO₃⁻

E. SO₄⁻²

F. Hg₂(NO₃)₂

G. NaNO₃

H. Hg⁺²

Answer:

C, D, E, H

Explanation:

The ions are formed after dissociation of the compound in the solution. When they're negatively charged, they're called anions, when they're negatively charged, they're called cations. If the ion is presented on both sides of the reaction, it is called a spectator ion.

Thus, the reaction given:

Na₂SO₄ + Hg(NO₃)₂ → HgSO₄ + 2NaNO₃

So, let's do the dissociation.

Na₂SO₄ is formed by the ions Na⁺ and SO₄⁻²;

Hg(NO₃)₂ is formed by the ions Hg⁺² and NO₃⁻;

HgSO₄ is formed by the ions Hg⁺² and SO₄⁻²;

NaNO₃ is formed by the ions Na⁺ and NO₃⁻.

Thus, the spectator ions are Na⁺, SO₄⁻², Hg⁺², and NO₃⁻.

7 0

3 years ago

A metal crystallizes in a body-centered cubic unit cell. The radius of one atom = 2.30 x 10 -8 cm. The density of the metal is 0

maw [93]

Answer:

25.41 g/mol is molar mass of metal.

Explanation:

Number of atom in BCC unit cell = Z = 2

Density of metal = $0.867 g/cm^3$

Edge length of cubic unit cell= a = ?

Radius of the atom of metal = r = $2.30\times 10^{-8} cm$

$a=2\times r=2\times 2.30\times 10^{-8} cm=4.60\times 10^{-8} cm$

Atomic mass of metal =M

Formula used :

$\rho=\frac{Z\times M}{N_{A}\times a^{3}}$

where,

$\rho$ = density

Z = number of atom in unit cell

M = atomic mass

$(N_{A})$ = Avogadro's number

a = edge length of unit cell

On substituting all the given values , we will get the value of 'a'.

$0.867 g/cm^3=\frac{2\times M}{6.022\times 10^{23} mol^{-1}\times (4.60\times 10^{-8} cm)^{3}}$

$M = 25.41 g/mol$

25.41 g/mol is molar mass of metal.

6 0

4 years ago

What is a cation and where can you find it on the periodic table?

LUCKY_DIMON [66]

Answer: Cations are positively charged ions.

Explanation: In cations the number of electrons is not equal to the number of positively charged protons. This is due to reason that cations donates their outer valence electrons making the atom less electronegative. The amount of electrons donated indicates the charge of the cation.

6 0

3 years ago

If anyone is good at figuring out the amount of heat released in chemistry PLS HELP!!!!!

KATRIN_1 [288]

Answer:

Option (3) 334J.

Explanation:

The following data were obtained from the question:

Mass (m) = 1g

Heat of fusion (ΔHf) = 334J/g

Heat (Q) =?

The heat released can be obtained as follow:

Q = m·ΔHf

Q = 1 x 334

Q = 334J.

Therefore, the heat released when 1g is converted to ice is 334J.

3 0

3 years ago