If spring constant is doubled, the mass on spring will be doubled as well. according to this formula, F=ke
k stands for spring constant and e stands for the length extended
Answer:
(a). The first wavelength is 401.0 nm.
(b). The metal's work function is 2.55 eV.
Explanation:
Given that,
Maximum kinetic energy = 0.65 eV
Second wavelength ![\lambda_{2}= \dfrac{2}{3}\times\lambda_{1}](https://tex.z-dn.net/?f=%5Clambda_%7B2%7D%3D%20%5Cdfrac%7B2%7D%7B3%7D%5Ctimes%5Clambda_%7B1%7D)
(a). We need to calculate the wavelength
Using equation of work function for first wavelength
.....(I)
For second wavelength,
![\dfrac{hc}{\lambda_{2}}-W_{0}=2.3\ eV](https://tex.z-dn.net/?f=%5Cdfrac%7Bhc%7D%7B%5Clambda_%7B2%7D%7D-W_%7B0%7D%3D2.3%5C%20eV)
Put the value of second wavelength
....(II)
By subtraction equation (I) from (II)
![0.5\dfrac{hc}{\lambda_{1}}=1.55](https://tex.z-dn.net/?f=0.5%5Cdfrac%7Bhc%7D%7B%5Clambda_%7B1%7D%7D%3D1.55)
![\lambda_{1}=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{3.1\times1.6\times10^{-19}}](https://tex.z-dn.net/?f=%5Clambda_%7B1%7D%3D%5Cdfrac%7B6.63%5Ctimes10%5E%7B-34%7D%5Ctimes3%5Ctimes10%5E%7B8%7D%7D%7B3.1%5Ctimes1.6%5Ctimes10%5E%7B-19%7D%7D)
![\lambda_{1}=4.010\times10^{-7}\ m](https://tex.z-dn.net/?f=%5Clambda_%7B1%7D%3D4.010%5Ctimes10%5E%7B-7%7D%5C%20m)
![\lambda_{1}=401.0\times10^{-9}\ m](https://tex.z-dn.net/?f=%5Clambda_%7B1%7D%3D401.0%5Ctimes10%5E%7B-9%7D%5C%20m)
![\lambda_{1}=401.0\ nm](https://tex.z-dn.net/?f=%5Clambda_%7B1%7D%3D401.0%5C%20nm)
(b). We need to calculate the work function
Using formula of work function
![W_{0}=(\dfrac{hc}{\lambda}-0.55)](https://tex.z-dn.net/?f=W_%7B0%7D%3D%28%5Cdfrac%7Bhc%7D%7B%5Clambda%7D-0.55%29)
Put the value into the formula
![W_{0}=(\dfrac{6.63\times10^{-34}\times3\times10^{8}}{1.6\times10^{-19}\times401.0\times10^{-9}}-0.55)](https://tex.z-dn.net/?f=W_%7B0%7D%3D%28%5Cdfrac%7B6.63%5Ctimes10%5E%7B-34%7D%5Ctimes3%5Ctimes10%5E%7B8%7D%7D%7B1.6%5Ctimes10%5E%7B-19%7D%5Ctimes401.0%5Ctimes10%5E%7B-9%7D%7D-0.55%29)
![W_{0}=2.55\ eV](https://tex.z-dn.net/?f=W_%7B0%7D%3D2.55%5C%20eV)
Hence, (a). The first wavelength is 401.0 nm.
(b). The metal's work function is 2.55 eV.
The Gay-Lussac's law or Amonton's law states that the pressure of a given amount of a gas is directly propotional to its temperature if its volume is kept constant .
P∝T
and
The Charles Law states that volume of given amount of gas at constant pressure is directly propotional to temperature.
V∝T
So, by Gay-Lussac's law if we increase the temperature the Pressure will increase and by Charles Law, if we increase the temperature the volume will increase.
Therefore, if the temperature of gas increases either the pressure of the gas, the volume of the gas, or both, will increase.
Hence,
Answer is option C
If <em>v</em> is the truck's final velocity, then
<em>v</em>² - (2.0 m/s)² = 2 * (2.00 m/s²) * (400.0 m)
<em>v</em>² = 1604 m²/s²
<em>v</em> = 40.05 m/s ≈ 40 m/s