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2 years ago

Help pls, see picture. Will mark Brainliest

Physics

2 answers:

lilavasa [31]2 years ago

6 0

Answer: The ball is thrown straight UP so when it asked whats the ball's velocity. It'll be graph ii. But.. to me, it seems that graph ii is the only one that provides a true reaction since the ball is thrown straight up. Or it could graph iii assuming the ball is thrown by a regular person. So when it asked for the position, I would pick iii.

Explanation: hope this made sense //Give thanks(and or Brainliest) if helpful (≧▽≦)//

Pani-rosa [81]2 years ago

5 0

Answer:

a ) option 2 is correct

b) -ve acceleration for upward motion ,0 acceleration at top point ,+ve acceleration on downward motion ...

Explanation:

mark me as brainliest ❤️

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The answer is gravity. I hope this helps.

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Answer:

The fraction of its energy that it radiates every second is $3.02\times10^{-11}$ .

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$\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}$

Given that,

Kinetic energy = 6.2 MeV

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$a=\dfrac{v^2}{r}$

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$a=\dfrac{\dfrac{1}{2}mv^2}{\dfrac{1}{2}mr}$

Put the value into the formula

$a=\dfrac{6.2\times10^{6}\times1.6\times10^{-19}}{\dfrac{1}{2}\times1.67\times10^{-27}\times0.51}$

$a=2.32\times10^{15}\ m/s^2$

We need to calculate the rate at which it emits energy because of its acceleration is

$\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}$

Put the value into the formula

$\dfrac{dE}{dt}=\dfrac{(1.6\times10^{-19})^2\times(2.3\times10^{15})^2}{6\pi\times8.85\times10^{-12}\times(3\times10^{8})^3}$

$\dfrac{dE}{dt}=3.00\times10^{-23}\ J/s$

The energy in ev/s

$\dfrac{dE}{dt}=\dfrac{3.00\times10^{-23}}{1.6\times10^{-19}}\ J/s$

$\dfrac{dE}{dt}=1.875\times10^{-4}\ ev/s$

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$\dfrac{\dfrac{dE}{dt}}{E}=\dfrac{1.875\times10^{-4}}{6.2\times10^{6}}$

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3 years ago

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1) The object slows down due to kinetic friction.
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