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IRINA_888 [86]
3 years ago
14

17- Find the magnitude of vector product \BxĀ| for A=– 23 +3Â and B = 2î – 3+ Å vectors.

Physics
1 answer:
aksik [14]3 years ago
8 0

Answer:

alam ko sagot pero mataas

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What is the most abundant gas in the atmosphere?
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Answer: Nitrogen

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Electrons are continuously being knocked out of air molecules by cosmic ray particles from space. Once the electrons are free, t
nata0808 [166]

(a) 1.25\cdot 10^{-14} J

The change in potential energy of the electron is given by:

\Delta U=q E d

where

q=1.6\cdot 10^{-19}C is the magnitude of the electron's charge

E=150 N/C is the magnitude of the electric field

d = 520 m is the distance through which the electron has moved

Substituting into the equation, we find

\Delta U=(1.6\cdot 10^{-19}C)(150 N/C)(520 m)=1.25\cdot 10^{-14} J

(b) 78 kV

The potential difference the electron has moved through is given by

\Delta V=Ed

where

E=150 N/C is the magnitude of the electric field

d = 520 m is the distance through which the electron has moved

Substituting into the equation, we find

\Delta V=Ed=(150 N/C)(520 m)=78,000 V=78 kV

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HOW FAR IS THE MOON?<br><br><br> [COVER UP QUESTION BORED}
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238,900 miles exactly

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Work done = Force X Distance

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Force = 3 430 000J / 14m
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Hope this helps!
8 0
2 years ago
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