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olga nikolaevna [1]
3 years ago
9

In which part of the wave are the particles of the medium closer together?

Physics
2 answers:
yuradex [85]3 years ago
8 0

B.compressions

Explanation:

This is a characteristics of the "longitudinal waves".

Longitudinal waves are waves where the oscillation of the particles of the medium occurs in a direction parallel to the direction of propagation of the wave (an example of longitudinal waves are sound waves). As a consequence, this oscillation creates some regions where particles are closer together, and other regions where particles are more spread apart. The former are called "compressions", while the latter are called "rarefactions".

Lesechka [4]3 years ago
6 0
B.) Compressions 
HOPPE IT HELPED
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I need help with this answer
7nadin3 [17]

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double replacement

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3 years ago
If the opening to the harbor acts just like a single-slit which diffracts the ocean waves entering it, what is the largest angle
soldi70 [24.7K]

Answer:

The angle that the wave would be \theta = sin ^{-1}\frac{2 \lambda}{D}

Explanation:

From the question we are told that  the  opening to  the  harbor acts just like a single-slit so a boat in the harbor that at angle equal to the second diffraction minimum would be safe and the  on at angle greater than the diffraction first minimum would be slightly affected

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               D sin \ \theta =m \lambda

where D is the slit with

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         m is the order of the minimum j

        \lambda is the wavelength

Now since in the question we are told to obtain the largest angle at which the boat would be safe

      And the both is safe at the angle equal to the second minimum then

    The the angle is evaluated as

           \theta = sin ^{-1}[\frac{m\lambda}{D} ]

Since for second minimum m= 2

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Uniform or constant motion in a straight line (rectilinear). Speed or velocity constant and/or acceleration constant. If motion is up and down and/or has an up and down component then acceleration omn earth will be g. g is about 10m/s/s.


speed = distance/time

velocity = displacement/time

s=distance ... u=initial speed ... v = final speed ... a = acceleration ... t = time


v=u+at

v^2=u^2+2as

s=ut+1/2at^2

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