Complete question is:
A 1200 kg car reaches the top of a 100 m high hill at A with a speed vA. What is the value of vA that will allow the car to coast in neutral so as to just reach the top of the 150 m high hill at B with vB = 0 m/s. Neglect friction.
Answer:
(V_A) = 31.32 m/s
Explanation:
We are given;
car's mass, m = 1200 kg
h_A = 100 m
h_B = 150 m
v_B = 0 m/s
From law of conservation of energy,
the distance from point A to B is;
h = 150m - 100 m = 50 m
From Newton's equations of motion;
v² = u² + 2gh
Thus;
(V_B)² = (V_A)² + (-2gh)
(negative next to g because it's going against gravity)
Thus;
(V_B)² = (V_A)² - (2gh)
Plugging in the relevant values;
0² = (V_A)² - 2(9.81 × 50)
(V_A) = √981
(V_A) = 31.32 m/s
Answer:
5 x 10^4 N/m^2
Explanation:
Pressure, force and area are related witg the following equation;
Pressure = Force /Area
From the question, we obtained the following information;
Force = 2N
Area = 0.00004m^2
Pressure =?
Pressure = Force /Area
Pressure = 2/0.00004
Pressure = 5 x 10^4N/m^2
Answer:
Sometimes may cause involuntary responses like twitching
Explanation:
The power exerted by the cyclist is determined as 50 W.
<h3>
Average power exerted by the cyclist</h3>
The power exerted by the cyclist is calculated as follows;
P = FV
where;
- F is the applied force
- V is velocity
P = 20 x 2.5
P = 50 W
Thus, the power exerted by the cyclist is determined as 50 W.
Learn more about power here: brainly.com/question/25263760
#SPJ1
Newton is used to measure force
The most used unit for the force measurement is "newton" which is the SI unit of the force
