Answer: Option (b) is the correct answer.
Explanation:
It is known that when a ray of light tends to travel from a denser to rarer medium then there occurs total internal reflection.
For a denser medium the refractive index is greater than that of a rarer medium. This means that for the given situation refractive index of medium 
is greater than medium 
.
this also means that incident angle must be greater than the critical angle of the medium.
Thus, we can conclude that the statement > must be true for total internal reflection to occur.
Answer:
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Explanation:
Your reasoning that the shadow is the shortest at mid-day is spot-on!
The wording of the question is the key to the answer. It says that the measurements were made in Summer. So this means that British Summer Time (BST) is being applied. BST is one hour ahead of Greenwich Mean Time and so what looks like 1pm is really 12 noon.
The safest sort of answer is to say that the shadow is shortest when the sun is at its highest point, and in this particular question that is at 1 pm because it is BST.
We are given with a volume of a cube equal to 512 cm3. In this case, when the volume is expressed to cubic meters, the volume will still stay the same but the number of cubic units would decrease. a centimeter is a smaller unit than a meter, hence the value given should be divided by 1 million to express to m3.
Answer:
Explanation:
helps recycle water
reduces the temperature extremes between day and night
recycles carbon dioxide and oxygen
protects the earth from harmful radiation
To solve this problem it is necessary to apply the concepts given in the kinematic equations of movement description.
From the perspective of angular movement, we find the relationship with the tangential movement of velocity through
Where,
Angular velocity
v = Lineal Velocity
R = Radius
At the same time we know that the acceleration is given as the change of speed in a fraction of the time, that is
Where
Angular acceleration
Angular velocity
t = Time
Our values are
Replacing at the previous equation we have that the angular velocity is
Therefore the angular speed of a point on the outer edge of the tires is 66.67rad/s
At the same time the angular acceleration would be
Therefore the angular acceleration of a point on the outer edge of the tires is 
