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Alexeev081 [22]
3 years ago
15

Where do tadpoles live? a. on land c. both on land and water b. in water d. none of the above

Physics
2 answers:
Bezzdna [24]3 years ago
5 0
Tadpoles live in water
ivanzaharov [21]3 years ago
3 0
Hey :)

Where Do tadpoles live?
Answer:Tadpoles Live in water
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Waves diffract the most when their wavelength is
djverab [1.8K]
<h2>Answer: about the same size of the gap  or slit</h2>

Diffraction happens when a wave (mechanical or electromagnetic wave, in fact, any wave) meets an obstacle or a slit .When this occurs, the wave bends around the corners of the obstacle or passes through the opening of the slit that acts as an obstacle, forming multiple patterns with the shape of the aperture of the slit.

Note that the principal condition for the occurrence of this phenomena is that the obstacle must be comparable in size (similar size) to the size of the wavelength.

In other words, when the gap (or slit) size is larger than the wavelength, the wave passes through the gap and does not spread out much on the other side, but when the gap size is equal to the wavelength, maximum diffraction occurs.

Therefore:

<h2>Waves diffract the most when their wavelength is <u>about the same size of the gap </u></h2>

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2 years ago
a hockey player exerts a force of 5 N over a distance of 0.3 m on a hockey puck. How much work is done on the hockey puck
Katen [24]

Answer: W = 1.5 J

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W = Fd

    = 5 N ( 0.3 M )

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7 0
3 years ago
How much energy must be absorbed by water with a mass of 0.5 kg in order to raise the temperature from 30°C to 65°C? Note: Water
Setler79 [48]

Answer:

Q = 73325 J or 73.325 KJ

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An unstable particle at rest spontaneously breaks into two fragments of unequal mass. The mass of the first fragment is 3.00 10-
kirill [66]

Answer:0.478 c

Explanation:

Given

mass of lighter Particle(m_1)=3\times 10^{-28} kg

mass of heavier Particle(m_2)=1.51\times 10^{-27} kg

speed of lighter particle(v_1)=0.834 c

Let speed of heavier particle=v_2

and Momentum of the particle is given by

P=\frac{mv}{\sqrt{1-(\frac{v}{c})^2}}

P_1=\frac{m_1v_1}{\sqrt{1-(\frac{v_1}{c})^2}}

P_1=\frac{3\times 10^{-28}\times 0.834 c}{\sqrt{1-(\frac{0.834 c}{c})^2}}

P_1=8.219\times 10^{-28} kg c

P_2=\frac{m_2v_2}{\sqrt{1-(\frac{v_2}{c})^2}}

as momentum is conserved therefore P_1=P_2

8.219\times 10^{-28} kg c=\frac{1.51\times 10^{-27}\times v_2}{\sqrt{1-(\frac{v_2}{c})^2}}

v_2=0.478 c

3 0
3 years ago
2 difference between calorimetry and calorimeter ​
garik1379 [7]

Calorimetry :

<em><u>the process of measuring the amount of heat released or absorbed during a chemical reaction</u></em>.

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8 0
2 years ago
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