Answer:
the energy absorbed is 4.477 x 10⁶ J
Explanation:
mass of the liquid, m = 13 kg
initial temperature of the liquid, t₁ = 18 ⁰C
final temperature of the liquid, t₂ = 100 ⁰C
specific heat capacity of water, c = 4,200 J/kg⁰C
The energy absorbed is calculated as;
H = mcΔt
H = mc(t₂ - t₁)
H = 13 x 4,200(100 - 18)
H = 4.477 x 10⁶ J
Therefore, the energy absorbed is 4.477 x 10⁶ J
Sorry I'm late, but here is the answer!
Answer:
Heat can travel from one place to another in three ways: Conduction, Convection, and Radiation. Both conduction and convection require the matter to transfer heat. Conduction is the transfer of heat between substances that are in direct contact with each other. Thermal energy is transferred from hot places to cold places by convection. Radiation is a method of heat transfer that does not rely upon any contact between the heat source and the heated object as is the case with conduction and convection. Heat can be transmitted through empty space by thermal radiation often called infrared radiation.
The vertical accelerations of the point a and point c are equal. because the vertical acceleration is due to the acceleration due to gravity. Acceleration due to gravity<span> may refer to: Gravitational acceleration, the acceleration caused by the gravitational attraction of massive bodies in general, which is equal to 9.8 m/s^2</span>
Answer:
In a nutshell, units of A and B are
and
, respectively.
Explanation:
From Dimensional Analysis we understand that
and
have length units (
) and
have time units (
). Then, we get that:
(Eq. 1)
(Eq. 2)
Now we finally clear each constant:
![A = \frac{[l]}{[l]^{3}}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B%5Bl%5D%7D%7B%5Bl%5D%5E%7B3%7D%7D)
![A = \frac{1}{[l]^{2}}](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B1%7D%7B%5Bl%5D%5E%7B2%7D%7D)
![B = \frac{[l]}{[t]}](https://tex.z-dn.net/?f=B%20%3D%20%5Cfrac%7B%5Bl%5D%7D%7B%5Bt%5D%7D)
In a nutshell, units of A and B are
and
, respectively.
Answer:
625 piece.
Explanation:
Let n be the required no of piece
200 litre = 200 x 10⁻³ m³ = 200 x 10⁻³ x 10³ kg = 200 Kg
mass of ice piece = n x 30 x /1000
Heat lost by ice pieces = (n x 30) / 1000 x ( 80 + 1 x 16⁰C)
Heat gained by water = 200 x 1 x 9⁰C
Heat lost = Heat gained
(n x 30) /1000 x ( 80 + 16 ) =200 x 9
2.88 n = 1800
n = 625