In the business cycle, the term that best fits the labeled point on the graph of Production output vs Time is Contraction
Answer:
See Explaination
Explanation:
class MagicSquare():
def __init__(self,side):
self.side=side
self.two_dimension=[]
for row in range(1,side+1):
row_line=[]
for col in range(1,side+1):
row_line.append(0)
self.two_dimension.append(row_line)
def display(self):
row=0
col=int((self.side-1)/2)
for i in range(1,self.side**2+1):
self.two_dimension[row][col]=i
row-=1
col+=1
if row==-1:
row=self.side-1
if col==self.side:
col=0
if self.two_dimension[row][col]==0:
continue
else:
row+=1
if row==self.side:
row==0
for line in self.two_dimension:
for num in line:
print("{0:>3}".format(num),end=" ")
print()
def main():
for i in range(1,14,2):
square=MagicSquare(i)
square.display()
print("----------------------------------------------------")
if __name__ == '__main__':
main()
Answer:
Yes.
Explanation:
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