Question

Solve y - 1 = 4y/3 - 2/3

Answer 1

$y-1 = \frac{4y}{3} - \frac{2}{3}$

Multiply both sides by 3 :

$y*3-1*3= \frac{4}{3} *3 - \frac{2}{3} *3$

$3y-3=4y-2$

Add 3 to both sides:

$3y - 3 + 3 = 4 y -2 + 3$

$3y = 4y+1$

Subtract 4 y from both sides:

$3y-4y = 4y+1-4y$

$-y = 1$

Divide both sides by -1 :

$\frac{-y}{-1} = \frac{1}{-1}$

$y = -1$

hope this helps!