The absorbance reported by the defective instrument was 0.3933.
Absorbance A = - log₁₀ T
Tm = transmittance measured by spectrophotometer
Tm = 0.44
Absorbance reported in this equipment = -log₁₀ (0.44) = 0.35654
True absorbance can be calculated by true transmittance, Tm = T+S(α-T)
S = fraction of stray light = 6%= 6/100 = 0.06
α= 1, ideal case
T = true transmittance of the sample
Tm = T+S(α-T)
now, T= Tm-S/ 1-S = 0.44-0.06/ 1-0.06 = 0.404233
therefore, actual reading measured is A = -log₁₀ T = -log₁₀ (0.404233)
i.e; 0.3933
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Answer:
d. Form ATP during glycolysis.
Explanation:
During oxidative phosphorylation, an oxidation-reduction reactions will happen and the electrons transferred and energy released will be used in the conversion of adenosine diphosphate (ADP) into adenosine triphosphate (ATP).
This happens as a step of glycolysis, wich is the process in which the organism breaks gluscose molecules to obtain energy.
Answer:they are chemically bound together and they retain their individual physical and chemical properties
Explanation:
Is formed with a strong acid and a weak base
