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goblinko [34]
3 years ago
10

Characteristics of the fungus kingdom (all of them)

Chemistry
1 answer:
Nana76 [90]3 years ago
5 0

- Fungi are "eukaryotic heterotrophs"

- Cell Walls contain a substance called Chitin

- All fungi are multicellular except yeast.

- Fungi are made up of Hyphae

- One hypha is only 1 cell thick

- The most common fungi is the DECOMPOSER

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For the reaction shown, calculate how many moles of NH3 form when 16.72 moles of reactant completely reacts:
Agata [3.3K]

Answer : The moles of NH_3 formed are, 22.3 moles.

Explanation : Given,

Moles of N_2H_4 = 16.72 mol

The given chemical reaction is:

3N_2H_4(l)\rightarrow 4NH_3(g)+2N_2(g)

From the balanced chemical reaction, we conclude that:

As, 3 moles of N_2H_4 react to give 4 moles of NH_3

So, 16.72 moles of N_2H_4 react to give \frac{4}{3}\times 16.72=22.3 moles of NH_3

Therefore, the moles of NH_3 formed are, 22.3 moles.

8 0
3 years ago
What patterns in the rock layer fossils helped you identify an extinction?
Dafna11 [192]
Often, the rock layers bookending the mass extinction are noticeably different in their compositions. These changes in the rocks show the effects of environmental disturbances that triggered the mass extinction and sometimes hint at the catastrophic cause of the extinction
8 0
3 years ago
Read 2 more answers
Which one is the catalyst?
yan [13]

Answer:

the catalyst is the two gray dots

5 0
3 years ago
?Al + ?H2SO4 → ?Al2(SO4)3 +3H2
AfilCa [17]

The answer is: 27 grams of aluminium.

Balanced chemical reaction: 2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂.

n(H₂) = 1.5 mol; amount of hydrogen.

Form chemical reaction: n(Al) : n(H₂) = 2 : 3.

n(Al) = 2 · 1.5 mol ÷ 3.

n(Al) = 1.0 mol; amount of aluminium.

m(Al) = n(Al) · M(Al).

m(Al) = 1 mol · 27 g/mol.

m(Al) = 27 g; mass of aluminium.

5 0
3 years ago
Assuming that a tank of gasoline contains 80 liters and that its density is 0.77 kg/liter, determine how many kg of co2 are prod
sleet_krkn [62]

Answer: -

If a tank of gasoline contains 80 liters and that its density is 0.77 kg/liter, 0.26 kg of CO₂ are produced for each tank of gasoline burned.

Explanation: -

Density of the gasoline = 0.77 kg / liter

Volume of the tank containing the gasoline = 80 liter.

Mass of gasoline produced from each tank

= Volume of the tank containing the gasoline x Density of the gasoline

= \frac{0.77 kg}{1 liter} x 80 liter

= 61.6 kg

Chemical formula of gasoline = C₈H₁₈

Molar mass of gasoline C₈H₁₈ = 12 x 8 + 1 x 18 = 114 g/ mol

Number of moles of C₈H₁₈ = \frac{61.6 g}{114 g} x 1 mol

= 0.54 mol of C₈H₁₈

The chemical equation for the burning of gasoline is

2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O

From the balanced equation we see

2 mol of C₈H₁₈ gives 16 mol of CO₂

0.54 mol of C₈H₁₈ gives \frac{16 mol CO2 x 0.54 mol C8H18}{2 mol C8H18} mol of CO₂

= 4.32 mol of CO₂

Molar mass of CO₂ = 12 x 1 + 16 x 3 =60 g / mol

Mass of CO₂ = Molar mass of CO₂ x Number of moles of CO₂

=\frac{60g x 4.32 mol}{1 mol}

= 259.2 g

= \frac{259.2}{1000}

= 0.259 Kg

= 0.26 kg rounded off to 2 significant figures.

Thus if a tank of gasoline contains 80 liters and that its density is 0.77 kg/liter, 0.26 kg of CO₂ are produced for each tank of gasoline burned.

4 0
3 years ago
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