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Harrizon [31]
3 years ago
13

Each periods starts with a strong metal except the first period true or false​

Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
7 0

Answer: True

Explanation:

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What percentage of the mass of 1 mole of CH3Cl is derived from carbon?​
steposvetlana [31]

Answer:

Element Symbol Atomic weight Atoms Mass percent

Carbon C                  12.0107               1              23.7894

Hydrogen H         1.00794                3         5.9892

Chlorine Cl                 35.453                 1       70.2213

Explanation:

3 0
3 years ago
What is the molarity of a solution prepared by dissolving 10.0g of kno3 in 250 ml of solution
maw [93]

Answer:

Mass of KNO3= 10g

Molar mass of KNO3 = 101.1032g/mol

Volume = 250ml = 0.25L

No of mole on of KNO3 = mass of KNO3/Molar mass of KNO3

no of mole of KNO3 = 10/101.1032

No of mole of KNO3 = 0.09891

molarity of KNO3 = no of mole of KNO3/Vol (L)

Molarity = 0.09891/0.25 = 0.3956M

Molarity of KNO3 = 0.3956M

8 0
3 years ago
What do scientist use to measure the volume of a substance
natali 33 [55]
Scientists use a Graduated Cylinder
3 0
3 years ago
Read 2 more answers
A sample of silicon rejected for use in an electronic circuit has an impurity of boron at a level of 3 parts per trillion. What
Law Incorporation [45]

Answer:

A. 3 x 10-12

Explanation:

Generally, the parts-per notation is used to represent very small concentration without any specific unit.

Parts per million is notated as 10^{-6}

Parts per billion is notated as 10^{-9}

Parts per trillion is notated as 10^{-12}

Hence, 3 parts per trillion will be written as 3 x 10^{-12}

The correct option is A.

6 0
3 years ago
Read 2 more answers
How many grams of XeF6 are required to react with 0.579 L of hydrogen gas at 6.46 atm and 45°C in the reaction shown below?
ankoles [38]
The chemical reaction equation for this is 

XeF6 + 3H2 ---> Xe + 6HF

Assuming gas behaves ideally, we use the ideal gas formula to solve for number of moles H2 with T = 318.15K (45C), P = 6.46 atm, V = 0.579L. Then we use the gas constant R = 0.08206 L atm K-1 mol-1.

we get n = 0.1433 moles H2

to get the mass of XeF6, 

we divide 0.1433 moles H2 by 3 since 1 mole XeF6 needs 3 moles H2 to react then multiply by the molecular weight of XeF6 which is 245.28 g/mole XeF6.

0.1433 moles H2 x \frac{1 mole XeF6}{3 moles H2} x \frac{245.28 g XeF6}{1 mole XeF6} = 11.71 g XeF6

Therefore, 11.71 g of XeF6 is needed to completely react with 0.579 L of Hydrogen gas at 45 degrees Celcius and 6.46 atm.
3 0
3 years ago
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