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ahrayia [7]
3 years ago
9

Can y’all please help me

Chemistry
1 answer:
Scrat [10]3 years ago
8 0
The measure is the same. :)
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Difference between dipole dipole and hydrogen bonding
riadik2000 [5.3K]

Hydrogen bonds are stronger than the dipole dipole attraction force present in any molecule.

<h3>What is bonding in molecules?</h3>

Bonding is a type of attraction force which is present between the different atoms or elements of any substance.

  • Dipole dipole attraction force is a weak force as compared to the hydrogen bonding and present between any two oppositely charged atoms.
  • Hydrogen bond is present between the hydrogen atom and more electronegative atoms like O, S, N and F.

Hence main difference is that hydrogen bond is only present between the hydrogen atom and more electronegative.

To know more about dipole-dipole force, visit the below link:
brainly.com/question/24197168

#SPJ4

8 0
2 years ago
If the distance between two objects is decreased to - of the original
Charra [1.4K]

Answer:

The new force will be \frac{1}{100} of the original force.

Explanation:

In the context of this problem, we're dealing with the law of gravitational attraction. The law states that the gravitational force between two object is directly proportional to the product of their masses and inversely proportional to the square of a distance between them.

That said, let's say that our equation for the initial force is:

F = G\frac{m_1m_2}{R^2}The problem states  that  the distance decrease to 1/10 of the original distance, this means:[tex]R_2 = \frac{1}{10}R

And the force at this distance would be written in terms of the same equation:

F_2 = G\frac{m_1m_2}{R_2^2}

Find the ratio between the final and the initial force:

\frac{F_2}{F} = \frac{G\frac{m_1m_2}{R_2^2}}{G\frac{m_1m_2}{R^2}}

Substitute the value for the final distance in terms of the initial distance:

\frac{F_2}{F} = \frac{G\frac{m_1m_2}{(\frac{R}{10})^2}}{G\frac{m_1m_2}{R^2}}

Simplify:

\frac{F_2}{F} = \frac{\frac{1}{100R^2}}{\frac{1}{R^2}}=\frac{1}{100}

This means the new force will be \frac{1}{100} of the original force.

8 0
3 years ago
Please help
docker41 [41]
i gotchuuu i’m checking my answer now
7 0
3 years ago
Us<br> What is the percent of O in<br> Cr2O3?<br> (Cr = 52.00 amu, O = 16.00 amu)<br> [? ]%
Gekata [30.6K]

The percent of O in  Cr₂O₃ : 31.58%

<h3>Further explanation</h3>

Given

Cr = 52.00 amu, O = 16.00 amu

Required

The percent of O

Solution

MW Cr₂O₃ = 2 x Ar Cr + 3 x Ar O

MW Cr₂O₃ = 2.52+3.16

MW Cr₂O₃ =152 amu

\tt \%O=\dfrac{3.Ar~O}{MW~Cr_2O_3}\times 100\%\\\\\%O=\dfrac{3.16}{152}\times 100\%\\\\\%O=31.58\%

8 0
3 years ago
Two samples of gold that have different temperatures are placed in contact with one another. Heat will flow spontaneously from a
galina1969 [7]
It is 50. This is because heat goes from higher temperatures to lower and nothing else in the options is lower.
7 0
4 years ago
Read 2 more answers
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