Answer:
T2 =21.52°C
Explanation:
Given data:
Specific heat capacity of sample = 1.1 J/g.°C
Mass of sample = 385 g
Initial temperature = 19.5°C
Heat absorbed = 885 J
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = Final temperature - initial temperature
885J = 385 g× 1.1 J/g.°C×(T2 - 19.5°C )
885 J = 423.5 J/°C× (T2 - 19.5°C )
885 J / 423.5 J/°C = (T2 - 19.5°C )
2.02°C = (T2 - 19.5°C )
T2 = 2.02°C + 19.5°C
T2 =21.52°C
Answer: Tin (Sn)
Explanation: The electron configuration for tin (Sn) is shown in the picture. It's last electrons are:
5s^2 4d^10 5p^2
The valence electrons are in the 5th electron shell and include 2 each in the 5s and 5p orbitals.
NaPO4 + KOH -> KPO4 + NaOH
already balance
Radioactive elements obey 1st order kinetics,
For 1st order reaction, relation between rate constant (k) and half life [t(1/2)] is,
k =

Also, for 1st order reaction, we have
t =
Given that: <span>the bones from a mastodon had lost 78.5% of their C14,
</span>∴ initial conc. of C14 = 100%, conc. of C14 left after time 't' = 21.5%
∴t =

= 1.2758 X 10^4 hours