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Elodia [21]
3 years ago
13

A net force of 3 N accelerates a mass of 3 kg at the rate of 1 m/s2. The acceleration of a mass of

Physics
1 answer:
Cloud [144]3 years ago
3 0

Answer:

,mkjh ,bkl m,

Explanation:

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The driver accelerates a 330.0 kg snowmobile, which results in a force being exerted that speeds up the snowmobile from 6.00 m/s
just olya [345]

Answer:

(a) 5610 kgm/s

(b) 5610 Ns.

(c)  78. 64 N

Explanation:

a. Change in momentum: This can be defined as the product of the mass of a body to its change in velocity. The S.I unit of change in momentum is kgm/s.

Mathematically, change in momentum is expressed as

ΔM = mΔv......................... Equation 1

Where ΔM = change in momentum, m = mass of snowmobile, Δv = change in velocity.

Given: m = 330 kg, Δv = v₂-v₁ = 23-6 = 17 m/s.

Note: v₁ and v₂ are the initial and the final velocity of the snowmobile.

ΔM = 330(17)

ΔM = 5610 kgm/s.

(b) Impulse: This can be defined as the product and force and time. The S.I unit of impulse is Ns.

Note: From Newton's second law of motion, impulse is equal to change in momentum.

Therefore,

I = ΔM................ Equation 2

Where I = impulse of the force.

Since ΔM = 5610 kgm/s.

Therefore

I = 5610 Ns.

Thus the impulse = 5610 Ns.

(c) Force: This can be defined as the product of the mass of a body and its acceleration. The S.I unit of force is Newton (N).

F = ma ................................. Equation 3

F = force, m = mass of the body, a = acceleration

But,

a = ( v₂-v₁)/t

Where v₂ = 23.0 m/s, v₁ = 6.0 m/s t = 60.0 s.

a = (23-6)/60

a = 0.283 m/s².

Substituting the value a and m into equation 3

F = 330(0.2383)

F = 78.639 N.

F ≈ 78. 64 N

8 0
3 years ago
A particularly scary roller coaster contains a loop-the-loop in which the car and rider are completely upside down. If the radiu
Pepsi [2]

Answer:

v = 10.89\ m/s

Explanation:

given,                          

radius of loop = 12.1 m                              

to find the minimum speed transverse by the rider to not to fall out upside down                                                                

centripetal force = \dfrac{mv^2}{r}

gravitational force  = m g

computing both the equation]

mg = \dfrac{mv^2}{r}

v = \sqrt{rg}

v = \sqrt{12.1 \times 9.8}

v = \sqrt{118.58}

v = 10.89\ m/s

5 0
3 years ago
Which of the following does not affect electrical resistance?
Gnesinka [82]
I think it's A) colour
6 0
3 years ago
A metal ball has a mass of 2kg and a volume of 6 m3. What is its density
Lena [83]

Answer: The answer is 333.3333 repeating

Explanation:

Divide the mass by the volume.

8 0
3 years ago
Read 2 more answers
With a quick flick of her wrist, an Ultimate Frisbee player can give a Frisbee an angular velocity of 4.00 revolutions per secon
Ad libitum [116K]

Answer:

a) w = 25.1 rad/s, b) θ  = 0.9599 rad , c) α = 328.1 rad/s²  d) t=  0.0765 s

Explanation: Let's work on this exercise with the equations of angular kinematics

a) The angular velocity is

    w = 4.00 rev / s (2π rad / 1 rev)  

     w = 25.1 rad/s

b) let's reduce the angle of degrees to radians

    θ = 55 ° (π rad / 180 °)

    θ  = 0.9599 rad

c) Let's use the initial angular velocity as the system part of the rest is zero

    w² = w₀² + 2 α θ

    α = w² / 2 θ

   α = 25.1²/2 0.9599

   α = 328.1 rad / s²

d)

   w = w₀ + α t

    t = w / α

    t = 25.1 / 328.1

    t=  0.0765 s

8 0
3 years ago
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