A net force of 3 N accelerates a mass of 3 kg at the rate of 1 m/s2. The acceleration of a mass of

What is the weight of a 4.5 kg mass on Earth?

swat32

Answer:

7.535×10^25 earth mass

Explanation:

for an approximate result,divide the mass value by 9.223e+18

4 0

3 years ago

Please help I have no idea

DochEvi [55]

Answer:

b

Explanation:

bbbbbbbbbbbbbbvgh c tyvftj xf

3 0

3 years ago

A uniform magnetic field passes through a horizontal circular wire loop at an angle 19.5 ∘ from the vertical. The magnitude of t

nlexa [21]

To solve this problem, we will apply the concepts related to Faraday's law that describes the behavior of the emf induced in the loop. Remember that this can be expressed as the product between the number of loops and the variation of the magnetic flux per unit of time. At the same time the magnetic flux through a loop of cross sectional area is,

$\Phi = BA Cos \theta$

Here,

$\theta$ = Angle between areal vector and magnetic field direction.

According to Faraday's law, induced emf in the loop is,

$\epsilon= -N \frac{d\Phi }{dt}$

$\epsilon = -N \frac{(BAcos\theta)}{dt}$

$\epsilon = -NAcos\theta \frac{dB}{dt}$

$\epsilon = -N\pi r^2 cos\theta \frac{d}{dt} ( ( 3.75 T ) + ( 3.05T/s ) t + ( -6.95 T/s^2 ) t^2)$

$\epsilon = -N\pi r^2 cos\theta( (3.05T/s)-(13.9T/s)t )$

At time $t = 5.71s$ , Induced emf is,

$\epsilon = -(1) \pi (0.220m)^2 cos(19.5\°)( (3.05T/s)-(13.9T/s)(5.71s))$

$\epsilon = 10.9V$

Therefore the magnitude of the induced emf is 10.9V

4 0

3 years ago

Read 2 more answers

What the planet after Venus

Aleonysh [2.5K]

Mercury and Venus are therefore closer to each other most of the time. But Earth is the planet closest to Venus. And that's why from here on Earth, Venus looks so big and luminous. Venus is the brightest thing in the night sky after the sun and the moon.

4 0

3 years ago

Read 2 more answers

Please, I need help with this question.

Jet001 [13]

The x and y components of the velocity vector is 17.32 m/s and 10 m/s respectively.

<h3>What is the x - component of the velocity?</h3>

The x-component of the ball's velocity is the velocity of the ball in the horizontal direction or x-axis.

The velocity of the ball in x-direction is calculated as follows;

Vx = V cosθ

where;

Vx is the horizontal velocity of the ball
V is the speed of the ball
θ is the angle of inclination of the speed

Vx = (20 m/s) x (cos 30)

Vx = 17.32 m/s

The velocity of the ball in y-direction is calculated as follows;

Vy = V sinθ

where;

Vy is the vertical velocity of the ball
V is the speed of the ball
θ is the angle of inclination of the speed

Vy = 20 m/s x sin(30)

Vy = 10 m/s

Learn more about x and y components of velocity here: brainly.com/question/18090230

#SPJ1

3 0

1 year ago