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dedylja [7]
3 years ago
9

A bob of mass of 0.18 kilograms is released from a height of 45 meters above the ground level. What is the value of the kinetic

energy gained by the bob at the ground level
Physics
1 answer:
goblinko [34]3 years ago
3 0
Plug into the equation K=1/2mv^2 sooo.. (1/2)(.18)v(you don't have velocity so use the equation for potential energy because you haveheight)(U=mgh so (.18kg)(9.8m/s)(45)=U (set U equal to K)  
(.18)(9.8)(45m)=1/2(.18)v^2
solve for v
don't forget to take the square root of v
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Answer:

44.64335 L

Explanation:

R = Gas constant = 8.314 J/mol K = 0.08205 L atm/mol K

P = Pressure

V = Volume

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1 denotes initial

2 denotes final

From ideal gas law we have

PV=nRT\\\Rightarrow V=\dfrac{nRT}{P}\\\Rightarrow V=\dfrac{2\times 0.08205\times 438}{0.44}\\\Rightarrow V=163.35409\ L

So,

P_1V_1=P_2V_2\\\Rightarrow V_2=\dfrac{P_1V_1}{P_2}\\\Rightarrow V_2=\dfrac{0.44\times 163.35409}{1.61}\\\Rightarrow V_2=44.64335\ L

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If a cruise ship is having troubles with buoyancy, then spread the weight of the ship over a greater volume.

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In the present condition, the solution for buoyancy problem faced by a cruise ship can be solved by decreasing the density of the ship. And the ship's density can be decreased by increasing the ship's volume or by spreading the ship's weight over a greater volume.

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