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3 years ago

An electric generator transforms mechanical energy into electrical energy. This process could be done by which of these?

Physics

2 answers:

Dimas [21]3 years ago

6 0

Answer:

its d

Explanation:

jeka57 [31]3 years ago

6 0

Answer:

D) Spinning a coil of wire near a large magnet.

Explanation:

From Faraday's law of induction, when a conducting coil of wire is placed in changing magnetic flux, an emf is induced which produces current in the coil.

Induced emf is given by:

$e = -\frac{d\phi}{dt}$

A generator is based on the same principle.

The mechanical energy of rotating coil is converted to electrical energy when current is induced. Thus, the correct option is D) Spinning a coil of wire near a large magnet.

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Three resistors of 100 W, 3900 W, and 1000 W are connected in series across a 200-V battery. What is the voltage drop across the

Gala2k [10]

Answer:

40 V

Explanation:

I will assume that the resistors are

100 and 3900 and 1000 OHMS <=====(NOT W)

In series , the resistances add together 100 + 3900 + 1000 = 5000 ohms total

V = IR

I = V / R so the total current will be 200 v / 5000 ohms = .04 amps

this is the current through all of the resistors

so for the 1000 ohm resistor V = IR .04 (1000) = 40 V

7 0

2 years ago

Please help

Hitman42 [59]

Answer:

3200 m/s

Explanation:

The speed of Sound through Argon is 319.

The speed of sound in any chemical element in the fluid phase has one temperature-dependent value. In the solid phase, different types of sound wave may be propagated, each with its own speed: among these types of wave are longitudinal (as in fluids), transversal, and (along a surface or plate) extensional.

If argon could exist as solid, then 3200 m/s is the best speed.

7 0

3 years ago

Read 2 more answers

A parallel-plate capacitor with plates of area 360 cm2 is charged to a potential difference V and is then disconnected from the

Softa [21]

Answer:

$Q=3.9825\times 10^{-9} C$

Explanation:

We are given that a parallel- plate capacitor is charged to a potential difference V and then disconnected from the voltage source.

1 m =100 cm

Surface area =S= $\frac{360}{10000}=0.036 m^2$

$\Delta d=0.8 cm=0.008 m$

$\Delta V=100 V$

We have to find the charge Q on the positive plates of the capacitor.

V=Initial voltage between plates

d=Initial distance between plates

Initial Capacitance of capacitor

$C=\frac{\epsilon_0 S}{d}$

Capacitance of capacitor after moving plates

$C_1=\frac{\epsilon_0 S}{(d+\Delta d)}$

$V=\frac{Q}{C}$

Potential difference between plates after moving

$V=\frac{Q}{C_1}$

$V+\Delta V=\frac{Q}{C_1}$

$\frac{Qd}{\epsilon_0S}+100=\frac{Q(d+\Delta d)}{\epsilon_0S}$

$\frac{Q(d+\Delta d)}{\epsilon_0 S}-\frac{Qd}{\epsilon_0S}=100$

$\frac{Q\Delta d}{\epsilon_0 S}=100$

$\epsilon_0=8.85\times 10^{-12}$

$Q=\frac{100\times 8.85\times 10^{-12}\times 0.036}{0.008}$

$Q=3.9825\times 10^{-9} C$

Hence, the charge on positive plate of capacitor= $Q=3.9825\times 10^{-9} C$

6 0

3 years ago

Which of the following are examples of both projectile motion and 2-dimensional motion?

Elanso [62]

Answer:

is answer

because of questions

5 0

2 years ago

Read 2 more answers

ken, 0.75 kg, moves toward a wall (his path normal to the wall) at 52 m/s. 13.0 ms after he touches the wall he pushes himself o

shtirl [24]

Q: ken, 0.75 kg, moves toward a wall (his path normal to the wall) at 52 m/s. 13.0 ms after he touches the wall he pushes himself off in the opposite direction at 60 m/s. What is the magnitude of the average force the wall exerts on Ken during this rapid maneuver

Answer:

-6461.54 N

Explanation:

From Newton's Fundamental equation,

F = m(v-u)/t.................... Equation 1

Where F = Force exerted in sonic, m = mass of ken, v = final velocity, u = initial velocity, t = time.

Given: m = 0.75 kg, v = - 60 m/s (opposite direction), u = 52 m/s, t = 13 ms = 0.013 s

Substitute into equation 1

F = 0.75(-60-52)/0.013

F = 0.75(-112)/0.013

F = -84/0.013

F = -6461.54 N

Note: The negative sign tells that the force act in opposite direction to the initial motion of ken.

Hence the magnitude of the average force of the wall = -6461.54 N

4 0

2 years ago