Hello from MrBillDoesMath!
Answer:
x = 1/2 (1 +\- i sqrt(23))
Discussion:
x \3x - 2 = (x/3)*x - 2 = (x^2)/3 - 2 (*)
1 \3x - 4 = (1/3)x - 4 (**)
(*) = (**) =>
(x^2)/3 -2 = (1/3)x - 4 => multiply both sides by 3
x^2 - 6 = x - 12 => subtract x from both sides
x^2 -x -6 = -12 => add 12 to both sides
x^2-x +6 = 0
Using the quadratic formula gives:
x = 1/2 (1 +\- i sqrt(23))
Thank you,
MrB
Answer:
225
Step-by-step explanation:
His answer was (x- +2) (x^2-9)
a) His mistake was he has x^2 in one of the parenthesis, to be fully factored you cannot have an exponent as part of the answer.
b) x^3 - 9x + 2x^2 -18
Reorder the terms:
x^3 +2x^2 -9x -18
Group the first two terms and the last two terms
(x^3 + 2x^2) -9x-18
Factor out the greatest common factor from each group:
x^2(x+2) - 9(x+2)
Factor the polynomial by factoring out the common factor once x+2:
(x+2) (x^2-9)
Rewrite 9 as 3^2:
(x+2) (x^2-3^2)
Factor one last time:
(x+2) (x+3) (x-3)
<h3>
Answer: B. Diagonals are congruent.</h3>
Explanation:
If the diagonals are congruent, then we'd have a rectangle. Any rectangle is a parallelogram, but not the other way around.
If we had a non-rectangular parallelogram, with none of the angles 90 degrees, then the diagonals will not be the same length.
Choices A, C and D are true for any parallelogram (rectangle or not).
