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posledela
3 years ago
15

Randal works at a zoo and is buying food for the animals. He buys 187 lbs of food for $1447.38. What is the unit rate?

Mathematics
2 answers:
m_a_m_a [10]3 years ago
8 0

Answer:

1 lbs=$7.90

Step-by-step explanation:

To solve this problem we need to use a proportion

\frac{lbs}{price} =\frac{187}{1,477.38}= \frac{1}{?}

to solve the proportion we would divide 1,477.38 by 187 which is 7.9 so the price per pound is 7.9

Jobisdone [24]3 years ago
3 0

Answer:

The unit rate would be $7.90 per pound

Step-by-step explanation:

All you have to do is divide $1.447.38 by 187 to find the unit rate

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3 years ago
When a breeding group of animals is introduced into a restricted area such as a wildlife reserve, the population can be expected
jasenka [17]

Answer:

A. Initially, there were 12 deer.

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. After 15 years, there will be 410 deer.

D. The deer population incresed by 30 specimens.

Step-by-step explanation:

N=\frac{12.36}{0.03+0.55^t}

The amount of deer that were initally in the reserve corresponds to the value of N when t=0

N=\frac{12.36}{0.33+0.55^0}

N=\frac{12.36}{0.03+1} =\frac{12.36}{1.03} = 12

A. Initially, there were 12 deer.

B. N(10)=\frac{12.36}{0.03 + 0.55^t} =\frac{12.36}{0.03 + 0.0025}=\frac{12.36}{y}=380

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. N(15)=\frac{12.36}{0.03+0.55^15}=\frac{12.36}{0.03 + 0.00013}=\frac{12.36}{0.03013}= 410

C. After 15 years, there will be 410 deer.

D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:

ΔN=N(15)-N(10)

ΔN=410 deer - 380 deer

ΔN= 30 deer.

D. The deer population incresed by 30 specimens.

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3 years ago
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FrozenT [24]

Answer:

36 right

Step-by-step explanation:

4 0
2 years ago
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