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solmaris [256]
3 years ago
6

How do you add the fractions 5/6 and 3/6?

Mathematics
1 answer:
Annette [7]3 years ago
7 0
5/6 + 3/6 = 8/6, you divide 6 into 8, and get 1 2/6, you can reduce that to 1 1/3

Sentence: one and one third 
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Find the equation of the graphed line.
GrogVix [38]

Answer:

  a.  y = -1/2x - 2

Step-by-step explanation:

The correct answer choice can be determined by finding the slope of the line. The slope is the ratio of rise to run.

__

<h3>slope</h3>

The x-intercept is 4 units left of the y-axis. As the line "runs" those 4 units, it "rises" -2 units to intercept the y-axis at -2. The slope of the line is ...

  m = rise/run = -2/4 = -1/2

In the slope-intercept form of the equation of a line, the slope is the coefficient of x. This information is sufficient to let us choose the first answer choice.

__

<h3>equation</h3>

The slope-intercept equation is ...

  y = mx +b . . . . . . . slope m, y-intercept b

We know the slope is -1/2, and the y-intercept is where x=0, at y=-2. Then the equation is ...

  y = -1/2x -2 . . . . . matches choice A

_____

<em>Additional comment</em>

When answering multiple-choice questions, you only need to do enough work to tell which answers are <em>not</em> viable.

When we plot the points, we see that the line has negative slope. (eliminates choice C). The slope is shallow, rather than steep (the x-intercept is farther from the origin than the y-intercept), so the magnitude of the slope is less than 1 and choices B and D are eliminated.

8 0
1 year ago
The dot plots show the ages of players on two soccer teams. Which statements are true? Check all that app The Lions have more va
Yuliya22 [10]

Answer:

B and D

B: the eagles have more variability in the ages of their players.

D: The Eagles have more players.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
HELP HELP HELP
mojhsa [17]

Answer:

2998 ; 17%

Step-by-step explanation:

Given the function:

t(c)=-3970.9(ln c)

c = % of carbon remaining ; t = time

1.) c = 47% = 47/100 = 0.47

t(0.47) = - 3970.9(In 0.47)

t = - 3970.9 * −0.755022

t = 2998.119

t = 2998

B.)

t = 7000

t(c)=-3970.9(ln c)

7000 = - 3970.9(In c)

7000 / - 3970.9 = In c

−1.762824 = In c

c = exp(−1.762824)

c = 0.1715596

c = 0.1715596 * 100%

c = 17.156% ; c = 17%

8 0
3 years ago
Read 2 more answers
Factorise 2x^2 - 3x -2 &lt; 0
Galina-37 [17]
Step 1: Factor 2 x^{2} - 3x -2
1. <span> Multiply 2 by -2, which is -4.</span>
2. <span>Ask: Which two numbers add up to -3 and multiply to -4?
</span>3. <span>Answer: 1 and -4
</span>4. Rewrite -3x as the sum of x and -4x

2 x^{2} +x-4x-2\ \textless \ 0


Step 2: <span>Factor out common terms in the first two terms, then in the last two terms.

</span>x(2x+1)-2(2x+1)\ \textless \ 0
<span>
Step 3: </span>Factor out the common term 2x+1

(2x+1)(x-2)\ \textless \ 0

Step 4: Solve for x

1. Ask: When will (2x+1)(x-2) equal zero?
2. Answer: When 2x + 1 = 0 or x-2=0
3. <span>Solve each of the 2 equations above:

</span>x=- \frac{1}{2} ,2
<span>
Step 5: </span>From the values of x <span>above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2

Step 6: P</span><span>ick a test point for each interval

</span>For the interval x\ \textless \ - \frac{1}{2} &#10;
Lets pick x=-1. Then, 2(-1) ^{2} -3 * -1 -2 \ \textless \  0
After simplifying, we get 3\ \textless \ 0, Which is false. 
Drop this interval.
<span>
For this interval - \frac{1}{2} \ \textless \ x\ \textless \ 2
Lets pick x=0. Then, 2* 0^{2} - 3 * 0-2\ \textless \ 0. After simplifying, we get -2\ \textless \ 0, which is true. Keep this <span>interval.

For the interval </span>x\ \textgreater \ 2

Lets pick x = 3. Then, 2 * 3  ^{2} -3*3-2\ \textless \ 0. After simplifying, we get 7\ \textless \ 0, Which is false. Drop this interval.

.Step 7: Therefore, 
- \frac{1}{2} \ \textless \ x\ \textless \ 2

Done! :)</span>
4 0
3 years ago
What is the local minimum value of the function? (Round answer to the nearest hundredth) g(x)=x^4-5x^2+4
Serhud [2]
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0

Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).

4 0
3 years ago
Read 2 more answers
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