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zhenek [66]
3 years ago
5

Anyone! Help me! (:o

Physics
2 answers:
Gnom [1K]3 years ago
5 0
You have written the answer within your question.


mass of 1kg metal is "1 kilogram"

but when you talk about it's weight
then,
it's weight is 9.8 Newton.
musickatia [10]3 years ago
5 0
Your question is exactly like asking "What color is an orange ?", or "Who is buried in Grant's tomb ?", or "What color is the White House ? .

The mass of 1 kilogram of anything is 1 kilogram.
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Someone please help me will give BRAILIEST!!!!!
ratelena [41]
The speed increases, because as the angle increases (the wing slants up more steeply), the air has to go farther to get over the wing.
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A 31.0 kg crate, initially at rest, slides down a ramp 2.6 m long and inclined at an angle of14.0° with the horizontal. Using th
mart [117]
The answer is 3.5m/s

8 0
3 years ago
a person with a mass of 75kg jumps on the trampoline the trampoline creates a fprce of 375n on them what is the acceleration of
Anarel [89]

Newton's second law allows calculating the response for the person's acceleration while leaving the trampoline is:

            -4.8 m / s²

Newton's second law says that the net force is proportional to the product of the mass and the acceleration of the body

            F = m a

Where the bold letters indicate vectors, F is the force, m the masses and the acceleration

The free body diagram is a diagram of the forces without the details of the body, in the attached we can see the free body diagram for this system

 

               F_t -W = m a

Whera F_t is the trampoline force

Body weight is

                W = mg

We substitute

              F_t - mg = ma

              a =\frac{F_t - m g}{m}

Let's calculate

              a = \frac{375 - 75 \ 9.8 }{75}

              a = -4.8 m / s²

The negative sign indicates that the acceleration is directed downward.

In conclusion using Newton's second law we can calculate the acceleration of the person while leaving the trampoline is

            -4.8 m / s²

Learn more here:  brainly.com/question/19860811

7 0
3 years ago
Please help me people
saveliy_v [14]

Answer :

(1) The density of asphalt is, 1200kg/m^3

(2) (a) Length, width and thickness of sheet in meter is, 0.35 m, 1.1 m and 0.015 m respectively.

(b) The volume and mass of slab is, 0.005775 m³ and 15.59 kg respectively.

Explanation :

<u>Part 1 :</u>

As we are given:

Mass of block = 90 kg

Volume of block = 0.075m^3

Formula used :

\text{Density of block}=\frac{\text{Mass of block}}{\text{Volume of block}}

Now put all the given values in this formula, we get:

\text{Density of block}=\frac{90kg}{0.075m^3}=1200kg/m^3

Thus, the density of asphalt is, 1200kg/m^3

<u>Part 2(a) :</u>

As we are given that:

Length of aluminium sheet = 35 cm

Width of aluminium sheet = 11 dm

Thickness of aluminium sheet = 15 mm

Now we have to convert these dimensions into meters.

Conversions used:

1 cm = 0.01 m

1 dm = 0.1 m

1 mm = 0.001 m

Length of aluminium sheet = 35 cm = 35 × 0.01 = 0.35 m

Width of aluminium sheet = 11 dm = 11 × 0.1 = 1.1 m

Thickness of aluminium sheet = 15 mm = 15 × 0.001 = 0.015 m

<u>Part 2(b) :</u>

First we have to calculate the volume of aluminium sheet.

Volume of aluminum sheet (cuboid) = Length × Width × Thickness

Volume of aluminum sheet (cuboid) = 0.35 m × 1.1 m × 0.015 m

Volume of aluminum sheet (cuboid) = 0.005775 m³

Now we have to calculate the mass of aluminium sheet.

\text{Density of aluminium}=\frac{\text{Mass of aluminium}}{\text{Volume of aluminium}}

2700kg/m^3=\frac{\text{Mass of aluminium}}{0.005775m^3}

\text{Mass of aluminium}=15.59kg

Thus, the volume and mass of slab is, 0.005775 m³ and 15.59 kg respectively.

7 0
3 years ago
Read 2 more answers
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Yakvenalex [24]
At 0 Kelvin everything stops moving ( even electrons ), so you could try to decrease the system's temperature
0 Kelvin = -273 Celsius
3 0
3 years ago
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