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Anika [276]
3 years ago
14

What is a cation and where can you find it in the periodic table?? Help pls

Chemistry
2 answers:
tester [92]3 years ago
5 0
A positively charged ion, one that would be attracted to the cathode in electrolysis.
almond37 [142]3 years ago
3 0

Answer: Cations are positively charged ions, due to loss of electrons in an atom

Explanation: Cations are usually metals and are found primarily on group 1 alkali metals, group 2 alkali earth metals, group 3 Boron group and transition metals.

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At their centers, all the jovian planets have cores made of:
Paul [167]

Answer:

The core of Jupiter and Saturn is made up of rock,metal and hydrogen compounds, while the core of Uranus and Neptune is made up of rock,metals,water, methane, and ammonia.

Explanation:

The Jovian planets include, Jupiter, Saturn, Uranus, and Neptune. These planets when compared to terrestrial planets are small, with dense cores and surrounded by layers of gas.

5 0
2 years ago
How many moles of aspartame are present in 1.00 mg of aspartame?
Diano4ka-milaya [45]

Answer:- There are 3.40*10^-^6 moles.

Solution:- It is a unit conversion problem where we are asked to convert mg of aspartame to moles. Aspartame is C_1_4H_1_8N_2O_5 and it's molar mass is 294.31 grams per mole.

mg are converted to grams and then the grams are converted to moles as:

1.00mg Aspartame(\frac{1g}{1000mg})(\frac{1mole}{294.31g})

= 3.40*10^-^6 moles of aspartame

So, there would be 3.40*10^-^6 moles of aspartame in 1.00 mg of it.

3 0
3 years ago
Which conclusion could be made from Ernest Rutherford’s gold foil experiment?
Tamiku [17]
The nucleus while large has a small ratio of mass when dealing with atoms, they are very spread out and are mostly solid with a blocky shape.
8 0
3 years ago
Read 2 more answers
The electrons stripped from glucose in cellular respiration end up in which compound? The electrons stripped from glucose in cel
Airida [17]
The final destination to where some of the electrons go to at the end of cellular respiration would be D. Oxygen. Assuming that this aerobic cellular respiration, the final electron acceptor is that of oxygen.
6 0
3 years ago
Calcium carbide (CaC2) reacts with water to form acetylene (C2H2) and Ca(OH)2.
Sergio [31]
The answer is -60.57 = -60.6 KJ.
CaC2(s) + 2 H2O(l) ---> Ca(OH)2(s) +C2H2(g) H= -127.2 KJ
Hf C2H2 = 226.77
Hf Ca(OH)2 = -986.2
<span>Hf H2O = -285.83
Now,

</span><span>add them up. 226.77 - 986.2 + (2*285.83) = -187.77 
</span><span>Add back the total enthalpy that is given in the question
 -187.77+127.2 = -60.57 </span>
8 0
3 years ago
Read 2 more answers
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