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fgiga [73]
3 years ago
14

What is the total number of valence electrons in a silicate ion sio32-?

Chemistry
1 answer:
olga2289 [7]3 years ago
4 0
Valence  electrons  are number  of the  electrons  in  the   outermost   shell of  an  atom
silicon  has  4   valence  electrons
oxygen  has  2  since  in SiO3^-2  they  are  3  this  make  valence   electrons  to  be   6
SiO3^-2  have   negative  charge of  two  thes  means  has   two  extra electrons hence   has  2  valence  electrons
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What are uses of metals??
blondinia [14]

Answer:

Different uses of Metals

Metals are usually very strong, most durable and highly resistant to everyday wear and tear. As such, they have been used since ancient times for a lot of things. And even today with advances in technology and a lot of other things the uses of metals have broadened greatly. Metals even play a key role in the economy. Let’s look at some important and popular metals uses.

In the Construction Industry

In electronics

In medicine

Machinery, Refractory and Automobiles

Decorative products

Other Uses

In the Construction Industry

Metals are the main component in the construction industry. Metals like iron, steel amongst others are the main materials used in construction of buildings and even homes.

In Electronics

Another important application of metals are in electronics. As metals are good conductors of electricity, they are used to making wires and parts for equipments and gadgets that function on electrical current. Popular examples include, TV, mobiles, fridge, iron, computers etc.

In medicine

If you are wondering how, well from a biological perspective metals are found as micro-elements in our bodies. Besides, the presence of metal elements is crucial for several functions like transmission of nerve impulses, oxygen flow, reaction between enzymes etc. Some medicines are therefore liaised with metal compounds to treat certain deficiencies or sickness. Metals like, iron, calcium, magnesium, potassium titanium, and aluminum are used commonly in medicine in the form of antacids.

Apart from this, most of the equipments and tools used are made from metals.

Machinery, Refractory and Automobiles

This is one of the most common use of metals. They are used extensively in manufacturing machines for industries, agriculture or farming and automobiles which include road vehicles, railways, airplanes, rockets etc. Here, the commonly used metals are iron, aluminum and steel.

Besides these, most of the utensils that is used in the kitchen are made from metals like steel, aluminum, and copper. Due to a high temperature withstanding nature metals are preferred the most.

Decorative products

Metals such as platinum, gold, and silver come under the category of precious metals and have high economical value. These metals are widely used in making jewellery sets or for some decorative piece.

Other Uses of Metals

Some other uses and applications of metals are, they play an important role in security as the metals are used in making locks, strong safe, doors etc. Apart from this, furnitures are made from metal these days. Metals also find their uses in the military where they are used to manufacturing weapons and ammunitions. Some metals are used in galvanizing to protect from rusting.

These are some popular uses of metal. To know more about metals, different types, properties of metals and more you can keep visiting BYJU’S or you can also download our app for interesting content and learning experience

3 0
3 years ago
Which chemical is the limiting reagent for the entire series of reactions? Why?
Reptile [31]
I'm assuming that you are asking a general question because you did not include an example.

The limiting reagent is the item in the reactants (reagents) that will run out first. This is because it limits what the reaction can produce, essentially causing the leftover elements/compounds to just sit there.
3 0
3 years ago
Read 2 more answers
Why does silicon have a high melting point
Igoryamba
If the bonds are held together tightly, as an ionic bond or even a covalent bond, there will need to be a strong force to separate those bonds. This would by why their would be a high melting point. Another reason would be re-activity. <span />
7 0
3 years ago
Chlorine and bromine are elements in Group VII.
Goryan [66]

Explanation:

Bromine is a chemical element with the symbol Br and atomic number 35. It is the third-lightest halogen, and is a fuming red-brown liquid at room temperature that evaporates readily to form a similarly coloured vapour. Its properties are intermediate between those of chlorine and iodine. Isolated independently by two chemists, Carl Jacob Löwig (in 1825) and Antoine Jérôme Balard (in 1826), its name was derived from the Ancient Greek βρῶμος ("stench"), referring to its sharp and disagreeable smell.

Bromine, 35Br

7 0
2 years ago
Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu
Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (<em>M)</em> is calculated from the following equation:

<em>M</em> = <em>n</em> ÷ <em>V</em>

where <em>n</em> is the number of moles of the solute in the solution, and <em>V</em> is the volume of the solution.

Accordingly, the number of moles of the solute is given by

<em>n</em> = <em>M</em> x <em>V</em>

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

<em>n </em>(1) = <em>M </em>(1) x <em>V </em>(1)

<em>n </em>(2) = <em>M </em>(2) x <em>V </em>(2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

<em>n</em> (1) = <em>n</em> (2)

and

<em>M</em> (1) x <em>V</em> (1)<em> </em>= <em>M</em> (2) x <em>V</em> (2)

For the stock solution, <em>M</em> (1) = 1.244 M, and <em>V</em> (1) is the volume needed. For the dilute solution, <em>M</em> (2) = 0,1281 M, and <em>V</em> (2) = 250.0 mL.

The volume of the stock solution needed, <em>V</em> (1), is calculated as follows:

<em>V</em> (1) = <em>M</em> (2) x <em>V</em> (2) ÷ <em>M</em> (1)

<em>V</em> (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

<em>V </em>(1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

7 0
2 years ago
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