Answer:
2.954 g
Explanation:
One banana contains 422 mg
One banana weighs 118 g
To make our calculations easier, we will convert both unit to the same power, that is both of them will be in g.
422 mg = 422/1000 = 0.422 g
If one banana contains 0.422 g of potassium, then 7 bananas(since he eats 1 per day) will weigh
0.422 * 7 = 2.954 g
Thus, after a week, he would have ingested at least 2.954 g of potassium.
I hope you understand the explanations. Thanks