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grandymaker [24]
3 years ago
10

Based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical equation:

Chemistry
1 answer:
Leni [432]3 years ago
5 0

Answer: (1)CaSO4 -> (2)O2 + (1)CaS

Explanation: edge 2020 chem

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a scientist is mixing a chemical for a solution foe an experiment. The solution contains 5/8 ounce of water and 1/6 ounce of sal
chubhunter [2.5K]
One whole and two eigths
6 0
4 years ago
Which of the following explains the process of radiation?
den301095 [7]

Answer:

When heat gets transferred through electromagnetic waves that move through space .

Explanation:

Radiation is the propagation of energy in the form of electromagnetic waves or subatomic particles through a vacuum or a material medium.

8 0
3 years ago
Suppose that 25,0 mL of a gas at 725 mmHg and 298K is converted to
posledela

The new volume : 21.85 ml

<h3>Further explanation</h3>

Given

V1=25,0 ml

P1=725 mmHg

T1=298K is converted to

T2=273'K

P2=760 mmHg atm

Required

V2

Solution

Combined gas law :

\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}

Input the value :

V2=(P1.V1.T2)/(P2.T1)

V2=(725 x 25 ml x 273)/(760 x 298)

V2=21.85 ml

5 0
3 years ago
A microwave can have a frequency of 3.8 X 1010Hz. How much energy does this microwave give off in joules?
Marina86 [1]

Answer:

2.52 x 10^{-23} J

Explanation:

The energy given off by the microwave can be determined by the application of Planck's energy formula:

E = hf

where: E is the required energy, h is Planck's constant (6.626 x 10^{-34}m^{2}Kg/s), and f is the frequency (3.8 x 10^{10} Hz).

So that;

E = 6.626 x 10^{-34} x 3.8 x 10^{10}

  = 2.51788 x 10^{-23}

Therefore, the energy released by the wave is 2.52 x 10^{-23} J.

3 0
3 years ago
4. When 1.00 L of 1.00 M Ba(NO3)2 solution at 25.0˚C is mixed with 1.00 L of 1.00 M Na2SO4 solution at 25.0˚C in a calorimeter,
myrzilka [38]

Answer:

The final temperature of the mixture is 28.11 °C

Explanation:

Step 1: Data given

Volume of 1.00 M Ba(NO3)2 = 1.00 L

Temperature = 25.0 °C

Volume of 1.00 M Na2SO4 = 1.00 L

enthalpy change is – 26 kJ per mol BaSO4

The specific heat of water is 4.18 J/g ·˚C

the density of water is 1.00 g/mL

Step 2: The balanced equation

Ba(NO3)2(aq) + Na2SO4(aq) → 2NaNO3(aq) + BaSO4(s)

Step 3: Calculate the total volume

Total volume = 1.00 L + 1.00 L = 2.00 L = 2000 mL

Step 4: Calculate mass

Mass = volume * density

Mass = 2000 mL * 1g/mL

Mass = 2000 grams

Step 5: Calculate moles BaSO4 formed

For 1 mol Ba(NO3)2 we need 1 mol Na2SO4 to produce 1 mol BaSO4

There is no limiting reactant, both Ba(NO3)2 and Na2SO4 will be completely be consumed (1 mol). We'll have 1.0 mol of BaSO4 produced.

Step 6: Calculate Q

Q = - ΔH

ΔH is negative so the reaction is exothermic, what means the temperature increases

Q is always positive, so Q = 26kJ = 26000 J

Step 6: Calculate the heat transfer

Q= m*c*ΔT

⇒with Q = the heat transfer = TO BE DETERMINED

⇒with m =the mass of the solution = 2000 grams

⇒with c= the specific heat of the solution = 4.18 J/g°C

⇒with ΔT = the change of temperature = T2 - T1 = T2 - 25.0

26000 = 2000 * 4.18 * (T2 - 25.0 °C)

3.11 = T2 - 25.0 °C

T2 = 25.0 + 3.11 °C

T2 = 28.11 °C

The final temperature of the mixture is 28.11 °C

7 0
3 years ago
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