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tigry1 [53]
3 years ago
5

Anyone good at chemistry ? Maybe you can help me out?

Chemistry
1 answer:
olga55 [171]3 years ago
4 0
I'm good at chemistry for some advice just message me here or roblox my username is rightchem7 .
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In dry climates, people often dig wells to find additional sources of water
vekshin1

Answer:

D i think, sorry if its wrong

Explanation:

3 0
2 years ago
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Which units represent destiny? Select all that apply.
ozzi
The basic units for density is \frac{mass}{volume} and any get of units that has those units in the proper place can be considered a density unit.  The ones that has those specifically are A, B, E and F
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3 years ago
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If you have 2.1 liters of hydrogen gas (at STP), what mass of hydrogen gas would you have?
GuDViN [60]

Answer:

0.19 g

Explanation:

Step 1: Given data

Volume of hydrogen at standard temperature and pressure (STP): 2.1 L

Step 2: Calculate the moles corresponding to 2.1 L of hydrogen  at STP

At STP (273.15 K and 1 atm), 1 mole of hydrogen has a volume of 22.4 L if we treat it as an ideal gas.

2.1 L × 1 mol/22.4 L = 0.094 mol

Step 3: Calculate the mass corresponding to 0.094 moles of hydrogen

The molar mass of hydrogen is 2.02 g/mol.

0.094 mol × 2.02 g/mol = 0.19 g

6 0
3 years ago
In a science lab, a student heats up a chemical from 10 °C to 25 °C which requires thermal energy of 30000 J. If mass of the obj
olganol [36]

Answer:

The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)

Explanation:

Step 1: Data given

Initial temperature = 10.0 °C

Final temperature = 25.0 °C

Energy required = 30000 J

Mass of the object = 40.0 grams

Step 2: Calculate the specific heat capacity of the object

Q = m* c * ΔT

⇒With Q = the heat required = 30000 J

⇒with m = the mass of the object = 40.0 grams

⇒with c = the specific heat capacity of the object = TO BE DETERMINED

⇒with ΔT = The change in temperature = T2 - T2 = 25.0 °C - 10.0°C = 15.0 °C

30000 J = 40.0 g * c * 15.0 °C

c = 30000 J / (40.0 g * 15.0 °C)

c = 50 J/g°C

The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)

3 0
3 years ago
Help plzzzzzzz ASAP!
Agata [3.3K]
I am going to say C. it has to do with the angles
8 0
3 years ago
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