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3 years ago

Reduce the following molecular formulas to empirical formulas. Please help!

Chemistry

1 answer:

zvonat [6]3 years ago

3 0

This is done by reducing each number by a common factor for each formula.

C3H6O6- all can be divided by 3 -> CH3O3 (you don't have to put a 1 for C, only if your teacher requests it. It is generally understood if not written)

H2O2- all can be divided by 2 -> H1O1 (had to put the 1's bc of the unintended language)

C8H8S2- all can be divided by 2 -> C4H4S

P5O15- all can be divided by 5- PO3

*****it is important to note that <em>all </em>numbers in the molecular formula are divided by the same thing to reduce them. decimals are <em>never </em>used in empirical formulas, only whole numbers.*****

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Each of the three known isotopes of hydrogen has blank protons in the nucleus

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Answer:

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3 years ago

Gemiola [76]

Answer: 1. magnesium hydroxide + sulfuric acid = magnesium sulphate + water

2. calcium hydroxide + hydrochloric acid = calcium chloride + water

3. lead hydroxide + nitric acid = lead nitrate + water

4. sodium hydroxide + sulfuric acid = sodium sulphate + water

5. potassium hydroxide + citric acid = potassium citrate + water

6. silver hydroxide + hydrochloric acid = silver chloride + water

7. aluminium hydroxide + phosphoric acid = aluminium phosphate + water

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

The balanced chemical equations are :

1. magnesium hydroxide + sulfuric acid = magnesium sulphate + water

$Mg(OH)_2(aq)+H_2SO_4(aq)\rightarrow MgSO_4(aq)+2H_2O(l)$

2. calcium hydroxide + hydrochloric acid = calcium chloride + water

$Ca(OH)_2(aq)+2HCl(aq)\rightarrow CaCl_2(aq)+2H_2O(l)$

3. lead hydroxide + nitric acid = lead nitrate + water

$Pb(OH)_2(aq)+2HNO_3(aq)\rightarrow Pb(NO_3)_2(aq)+2H_2O(aq)$

4. sodium hydroxide + sulfuric acid = sodium sulphate + water

$NaOH(aq)+H_2SO_4(aq)\rightarrow Na_2SO_4(aq)+H_2O(l)$

5. potassium hydroxide + citric acid = potassium citrate + water

$KOH(aq)+C_6H_8O_7(aq)\rightarrow C_6H_7O_7K(aq)+H_2O(l)$

6. silver hydroxide + hydrochloric acid = silver chloride + water

$AgOH(aq)+HCl(aq)\rightarrow AgCl(s)+H_2O(l)$

7. aluminium hydroxide + phosphoric acid = aluminium phosphate + water

$Al(OH)_3(aq)+H_3PO_4(aq)\rightarrow AlPO_4(aq)+3H_2O(l)$

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Answer:

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balandron [24]

B. .175

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