Answer:
with 7 valence electrons.
Explanation:
Bromine has 7 unpaired (valence) electrons in its outer shell, and a total of 35 elecrons. Its <em>4s</em> orbital is completely filled with 2 electrons.
The closest answer from the options would be option D.
I hope this helps.
The bond angle in H2Se would be predicted should be less than 109.5 degrees. Particle shapes can be anticipated in light of Lewis dab structure utilizing the VSEPR hypothesis. VSEPR remains for Valence Shell Electron Pair Repulsion. It expresses that electron matches in the valence shell of a particle repulse each other; their sub-atomic geometry is the consequence of this shock.
Answer: D=8.27 g/cm³
Explanation:
Density is mass/volume. Mass is in grams and volume is in liters. In this case, the problem wants our volume to be in cm³. All we need to do is to make some conversions to convert kg/m³ to g/cm³.
With this equation, the m³ and kg cancel out, and we are left with g/cm³.
D=8.27 g/cm³
Answer:
a) (CH3)3N
b) 4-methylpyridine
Explanation:
Let us bear in mind that the basicity of amines depend on;
1) the availability of the lone pair
2) the stability of the conjugate acid of the amine.
In the gaseous phase, the basicity of the amine strictly depends on the availability of the lone pair. The tertiary amine is better able to accept a proton in the gaseous phase since it is surrounded by three methyl groups having an electron pushing effect thereby reinforcing the lone pair on the nitrogen. This order is reversed in solution due to solvation.
Here again, the electron donation to the nitrogen bearing the lone pair is important. The 4-methylpyridine is more basic than 2-methylpyridine to BMe3 due to steric hindrance that hinders the bonding of 2-methylpyridine to BMe3.
