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Ludmilka [50]
3 years ago
13

Reduce the following molecular formulas to empirical formulas. Please help!

Chemistry
1 answer:
zvonat [6]3 years ago
3 0
This is done by reducing each number by a common factor for each formula.

C3H6O6- all can be divided by 3 -> CH3O3 (you don't have to put a 1 for C, only if your teacher requests it. It is generally understood if not written)

H2O2- all can be divided by 2 -> H1O1 (had to put the 1's bc of the unintended language) 

C8H8S2- all can be divided by 2 -> C4H4S 

P5O15- all can be divided by 5- PO3

*****it is important to note that <em>all </em>numbers in the molecular formula are divided by the same thing to reduce them. decimals are <em>never </em>used in empirical formulas, only whole numbers.*****
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The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I2 will form 3.58 g of NI3?
Nat2105 [25]
To answer the problem above first we need to find the difference of molar mass of NI3 from I2, 394.71 g/mol - 253.80 g/mol = 140.91 g/mol. Knowing the molar mass of the difference of NI3 from I2, in equation mass (g) / moles (mol) = molar mass, then we substitute. 3.58g / moles = 140.91 g/mol.
moles = 3.58 / 140.91 = 0.025 moles.
6 0
4 years ago
Which element has a larger atomic radius than sulfur? chlorine cadmium fluorine oxygen
zhuklara [117]

Answer:

  • <u>Cadmium has larger atomic radius than sulfur.</u>

Explanation:

Down a period, atomic radii decrease from left to right due to the increase in the number of protons and electrons across a period: when a proton is added the pull of the electrons towards the nucleus is larger, so the size of the atom decreases.

Hence, you can compare the elements that belong to a same period and predict that the atom with lower atomic number (number of protons) will haver larger atomic radius. With that:

  • Oxygen and fluorine are in the period 3, being oxygen to the left of fluorine, so oxygen is larger than fluorine.

  • Sulfur and chlorine are in the period 4, being sulfur to the left of chlorine, so sulfur is larger than chlorine.

Now see whan happens down a group. Atomic radius increases from top to bottom within a group due to electron shielding. That permits you to compare the size of the elements in a group:

  • Fluorine and chlorine are in the same group (17), with chlorine directly below fluorine, so the atomic radius of chlorine is larger than the atomic radius of fluorine.

  • Sulfur and oxygen are in the same group (16), with sulfur directlly below oxygen, so sulfur the atomic radius of sulfur is larger than the atocmi radius of oxygen.

So far, you can rank the atomic radius of sulfur, chlorine, fluorine, and oxygen, in increasing order as:

  • O < F < Cl < S, concluding that O, F, and Cl have smaller atomic radius than S.

Cadmiun, Cd, is to the left and below sulfur, so both electron shielding (down a group) and increase of the number of protons (down a period) lead to predict the cadmium has a larger atomic radius than sulfur.

8 0
3 years ago
Le Chatelier's Principle. For the reaction below, if the equilibrium concentrations were NH3 = 2 x 10-4, H3O+ = 2 x 10-4M and NH
telo118 [61]

Answer:

Explanation:

NH3 + H3O+ --> NH4+ + H2O

equllibrium constant =K = [ H2O] [NH4+] / [NH3] [H3O+ ]

                                      =

by inserting thier respecive values can you calcaulte, by the way coniseder  [ H2O] =1 ,

6 0
4 years ago
Which of the following is an example of an exothermic reaction? silt settling out of muddy water, bubbles forming in soda, photo
Rudik [331]
Fireworks
An exothermic reaction is one where the products have lower energy than the reactants, so the reaction yields energy. The chemical compounds present in firework fuel release a lot of energy upon oxidation. Photosynthesis is endothermic, settling of silt is not a chemical reaction, it is a physical change. Finally, the bubble formation in soda is not exothermic; otherwise, the sodas would become very hot very fast.
4 0
3 years ago
If one iron nail weighs 2.0 grams, what would be the mass of 6.022 x 10^23 nails?
Maru [420]

Answer:

1.2x10^{24}g

Explanation:

Hello!

In this case, it is possible to treat this problem by using a proportional factor which indicates one iron nail equals 2.0 grams:

\frac{2.00g}{1nail}

Now, for an amount of 6.022x10²³ nails, the corresponding mass will be:

6.022x10^{23}nail*\frac{2.00g}{1nail} \\\\1.2x10^{24}g

Best regards!

8 0
3 years ago
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