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iragen [17]
2 years ago
15

The diagram shows 3 ships A, B and C at sea.

Mathematics
1 answer:
Wittaler [7]2 years ago
5 0

Answer:

5km + 4.5km +2.7km = 12.3km

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Can somebody plz answer all of them correct! (Only if u done this before)
swat32

Answer:

23) 53/100

24)2/5

25)3/5

26)11/50

27)17/50

28)19/1000

29)4/5

30)1/250

31)9/25

32)1 3/10

33)11 1/2

34) 7 3/40

Step-by-step explanation: Hope this helps!

7 0
3 years ago
Find the value of x in the equation. 6x+48=60
aliina [53]
First do 60-48 then that equals 12. Next do 12 divide by 6x and your answer is 2
7 0
3 years ago
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Using the geometric mean and Pythagorean theorem, calculate the values of the missing sides. Round your answers to the thousandt
Pachacha [2.7K]

Answer:

a = 9.849

b = 20.25

c = 491.03

Step-by-step explanation:

By using Pythagoras theorem in the right triangle BDC,

(Hypotenuse)² = (Leg 1)² + (Leg 2)²

BC² = BD² + DC²

a² = 9² + 4²

a = \sqrt{(81+16)}

a = \sqrt{97}

a = 9.8489

a ≈ 9.849 units

By mean proportional theorem,

\frac{\text{DC}}{\text{BD}}=\frac{\text{BD}}{\text{AD}}

AD × DC = BD²

b × 4 = 9²

b = \frac{81}{4}

b = 20.25 units

BY Pythagoras theorem in ΔADB,

AB² = AD² + BD²

c² = b² + 9²

c² = (20.25)² + 9²

c² = 410.0625 + 81

c = 491.0625

c = 491. 063 units

6 0
3 years ago
How does the volume of an oblique cone change if the height is reduced to 2/3 of its original size and the radius is doubled
spayn [35]

The volume of oblique cone =\frac{1}{3} \pi r^{2} h

Now radius is doubled is now it is 2r

And height is reduced to 2/3 of its original size that is 2/3 h

So plugging the values we get volume

New Volume = \frac{1}{3} \pi (2r)^2 (\frac{2}{3} h)

= \frac{1}{3} \pi 4r^2 (\frac{2}{3} h) = \frac{8}{6} \pi r^{2} h =\frac{8}{2} (\frac{1}{3} \pi r^{2} h )=4*(\frac{1}{3} \pi r^{2} h )

It means the volume becomes 4 times

3 0
3 years ago
BRAINLIEST HELP!!! Simplify the expression; -15+[(6-1)-(-1-19)]
Korolek [52]

The answer you want will be 10.

Hope it helps!!

6 0
3 years ago
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