Answer:
9.11*10^-4 %
Step-by-step explanation:
To find the probability, you simply need to find the possible outcomes that allows no rooks to be in danger, and the possible amount of ways to place the rooks.
For the first outcome, you start by putting 1 rook in the first columns, you have 8 possible rows to do this. The next rook in the next column will only have 7 possible rows, as you have to exclude the one where the previous rook is located. The next rook, 6 possibilities, the next 5, and so on. So we conclude that the total amount of ways so that none of the rooks can capture any of the other rooks is 8*7*6*5*4*3*2*1 = 8! = 40320
In order to find the total amount of ways to place the rooks, you can just use a combinatoric:
![\left[\begin{array}{ccc}64\\8\end{array}\right]= \frac{64!}{8!(64-8)!} = 4.43*10^9](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D64%5C%5C8%5Cend%7Barray%7D%5Cright%5D%3D%20%5Cfrac%7B64%21%7D%7B8%21%2864-8%29%21%7D%20%3D%204.43%2A10%5E9)
Then:
P = 
Answer:
See explanation.
Step-by-step explanation:
Tyler wrote everything correct, except he multiplied some incorrectly. 2x times 5 is 10x, not 7x. And 3 times 5 is 15, not 8. The bottom left and right boxes are incorrect.
This is some simple Algebra
So it's 4x+16=-2
We subtract 16 from both sides
4x=-18
Sivide both sides by 4
X=-4.5
If you need more of an explanation I am happy to elaborate
Answer:
∠AOC
Step-by-step explanation:
The statement "A to O to C" is talking about each of the points that form an angle. Each point is given a letter as its name.
The symbol ∠ <u>means angle</u>.
You need two lines to form an angle, and you need two points to form a line. By reusing one of the points, you need three points to form an angle. The point that is being reused is always the point in the middle, in this case, that point is called 'O'.
Equilateral triangles have equal sides
117/3 = 39 mm. All the sides equal to
39 mm
Solution: 39mm
