1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andre45 [30]
3 years ago
13

F = 3e8 divided by 6.56E-9 NO ANSWERS?

Physics
1 answer:
julsineya [31]3 years ago
7 0

Answer:

0.461\times10^{17}

Explanation:

The expression can be written as:

\frac{3\times10^8}{6.5\times10^{-9}}

That can be further simplified as:

\frac{3}{6.5}\times \frac{10^8}{10^{-9}}

Using \frac{1}{a^{-x}} = a^x\\\\ \frac{1}{10^{-9}}=10^9

Also, using the law of indices:

a^x\times a^y= a^{(x+y)}\\\\10^8\times10^9= 10^{(8+9)}= 10^{17}

Also, \frac{3}{6.5}=0.465

Now, the expression becomes:

=0.465\times10^8\times10^9\\=0.465\times10^{(8+9)}\\\\=0.465\times10^{17}

Therefore, the answer is 0.465\times10^{17}.

You might be interested in
If you pull with your lower leg such that you exert a 90 N force on the cord attached to your ankle, determine the magnitude of
guapka [62]

This question is incomplete, the missing diagram is uploaded along this answer below.

Answer:

- the magnitude of the tension force exerted by the hamstring muscles on the leg is 990 N

- the magnitude of compression force at the knee joint is 900 N

Explanation:

Given the data in the question and diagram below;

Net torque = 0

Torque = force × lever arm

so

F_{ConF  × ( 15.0 in + 1.5 in ) = T_{HonL × 1.5 in

given that F_{ConF = 90 N

90 × ( 15.0 in + 1.5 in ) = T_{HonL × 1.5 in

90 N × 16.5 in =  T_{HonL × 1.5 in

T_{HonL = ( 90 N × 16.5 in ) / 1.5 in

T_{HonL = 990 N

Therefore, the magnitude of the tension force exerted by the hamstring muscles on the leg is 990 N

b) magnitude of compression force at the knee joint;

In equilibrium, net force = 0

along horizontal

F_{FonB - T_{HonL + F_{ConF = 0

we substitute

F_{FonB - 990 + 90 = 0

F_{FonB - 900 = 0

F_{FonB = 900 N

Therefore, the magnitude of compression force at the knee joint is 900 N

4 0
4 years ago
Two bullets have masses of 3.0 g and 6.0 g respectively. Both are fired with a speed of 40.0 m/s.(a) Which bullet has more kinet
Stolb23 [73]

Answer:

(a) The bullet with a mass of 6.0 g

(b) \frac{K_2}{K_1}=2

Explanation:

(a) Kinetic energy is defined as:

K=\frac{mv^2}{2}

So, we have:

K_1=\frac{3*10^{-3}kg(40\frac{m}{s})^2}{2}\\K_1=2.4J

K_2=\frac{6*10^{-3}kg(40\frac{m}{s})^2}{2}\\K_2=4.8J

The bullet with a mass of 6.0 g have more kinetic energy

(b) We have m_2=2m_1(1) and v_1=v_2(2). So:

K_1=\frac{m_1v_1^2}{2}\\K_2=\frac{m_2v_2^2}{2}\\\frac{K_2}{K_1}=\frac{\frac{m_2v_2^2}{2}}{\frac{m_1v_1^2}{2}}(3)

Replacing (1) and (2) in (3):

\frac{K_2}{K_1}=\frac{\frac{2m_1v_1^2}{2}}{\frac{m_1v_1^2}{2}}\\\frac{K_2}{K_1}=2

4 0
3 years ago
For the reaction shown below, which statement is correct? Ba(OH)2 + 8H20 + 2NH4NO3 + heat ?10H2O + 2NH3 + Ba(NO3)2
adell [148]
I believe the correct answer is B
7 0
3 years ago
A truck initially traveling at a speed of 22 m/s increases at a constant rate of 2.4 m/s^2 for 3.2s. What is the total distance
FinnZ [79.3K]

Answer:

82.7 m

Explanation:

u= 22m/s

a= 2.4 m/s^2.

t= 3.2 secs

Therefore the distance travelled can be calculated as follows

S= ut + 1/2at^2

= 22 × 3.2 + 1/2 × 2.4 × 3.2^2

= 70.4 + 1/2×24.58

= 70.4 + 12.29

= 82.7 m

Hence the distance travelled by the truck is 82.7 m

6 0
3 years ago
The position function x (6.0 m) cos[(3p rad/s)t p/3 rad]gives the simple harmonic motionof a body. at t 2.0 s, what are the(a) d
Daniel [21]

The correct formula for this simple harmonic motion is:

x = (6.0) cos [ (3 pi) t + pi/3 ] 

 

A. Calculating for displacement x at t = 2:

x =6.0 cos (19/3 pi)
x = 6 (0.5)

x = 3 m

 

<span>B. Velocity is equivalent to the 1st derivative of the equation. v = dx / dt </span>

<span> Velocity v = dx/dt = -18 pi sin (3pi t + pi/3) </span>

v = - 18 pi sin (6pi + pi/3)

v = 49.0 m/s

 

<span>C. Acceleration is the 2nd derivative or the 1st derivative of velocity dv / dt</span>
Acceleration a = dv/dt = -54 pi^2 cos(3pi t + pi/3) 

a = -54 pi^2 cos(3pi * 2 + pi/3)

a = 386.34 m/s^2

D. Phase = pi/3 

E. frequency f= 3pi/2pi = 1.5Hz 


<span>F. period = 1/f = 1/1.5 = .6667sec </span>

5 0
4 years ago
Other questions:
  • The ___________ effect is the change of pitch heard when the source of the sound approaches and then moves away from a stationar
    8·2 answers
  • Answer all of these questions
    8·1 answer
  • Consider a father pushing a child on a playground merry-go-round. The system has a moment of inertia of 84.4 kg · m². The father
    12·1 answer
  • Are you sure? Its either tranaverse or longitudinal
    7·1 answer
  • Why is that when an ice is compress on someones head he dies
    10·1 answer
  • What is the tendency of a material to oppose the flow of charge?
    11·2 answers
  • 14) A barking dog delivers about 1 mW of power, which is assumed to be uniformly distributed in all directions. What is the inte
    13·1 answer
  • A block of mass m is released from rest at a height R above a horizontal surface. The acceleration due to gravity is g. The bloc
    6·1 answer
  • The difference in a brass rod and steel rod is same as 12cm at all temperature .Find the length of the rod at 0°C.​(Alpha b =18×
    7·1 answer
  • Sally can run 3 flights of stairs in 25 seconds. Each stair is 0.15 meter tall and there are 15 stairs in one flight. Sally has
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!