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Andre45 [30]
3 years ago
13

F = 3e8 divided by 6.56E-9 NO ANSWERS?

Physics
1 answer:
julsineya [31]3 years ago
7 0

Answer:

0.461\times10^{17}

Explanation:

The expression can be written as:

\frac{3\times10^8}{6.5\times10^{-9}}

That can be further simplified as:

\frac{3}{6.5}\times \frac{10^8}{10^{-9}}

Using \frac{1}{a^{-x}} = a^x\\\\ \frac{1}{10^{-9}}=10^9

Also, using the law of indices:

a^x\times a^y= a^{(x+y)}\\\\10^8\times10^9= 10^{(8+9)}= 10^{17}

Also, \frac{3}{6.5}=0.465

Now, the expression becomes:

=0.465\times10^8\times10^9\\=0.465\times10^{(8+9)}\\\\=0.465\times10^{17}

Therefore, the answer is 0.465\times10^{17}.

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A proton travels with a speed of 4.2×106 m/s at an angle of 30◦ west of north. A magnetic field of 2.5 T points to the north. Fi
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Answer:

8.4\cdot 10^{-13} N

Explanation:

The magnitude of the magnetic force on the proton is given by:

F=qvB sin \theta

where:

q=1.6\cdot 10^{-19} C is the proton charge

v=4.2\cdot 10^6 m/s is the proton velocity

B=2.5 T is the magnetic field

\theta=30^{\circ} is the angle between the direction of v and B

Substituting into the formula, we find

F=(1.6\cdot 10^{-19}C)(4.2\cdot 10^6 m/s)(2.5 T) sin 30^{\circ}=8.4\cdot 10^{-13} N

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