Assume your mass is 60 kg. The acceleration due to gravity is 9.8 m/s 2 . How much work against gravity do you do when you climb
1 answer:
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Answer:
The current through the inductor at the end of 2.60s is 9.7 mA.
Explanation:
Given;
emf of the inductor, V = 41.0 mV
inductance of the inductor, L = 13 H
initial current in the inductor, I₀ = 1.5 mA
change in time, Δt = 2.6 s
The emf of the inductor is given by;
Therefore, the current through the inductor at the end of 2.60 s is 9.7 mA.
Answer:
50 W
Explanation:
<h3><u>Given :</u></h3>- Force applied = 100 N
- Distance covered = 5 metres
- Time = 10 seconds
Power
<h3><u>Solution :</u></h3>For calculating power, we first need to know about the work done.
Now, substituting values in the above formula;
Work = 100 × 5
= 500 Nm or 500 J
We know that,
Substituting values in above formula;
Power = 500/ 10
= 50 Nm/s or 50 W
Hence, power = 50 W .
Answer:
6s
Explanation:
Assume it is dropped from rest and the gravitational acceleration is 10
By the equation of motion under constant acceleration:
180 = (0)t+10(t^2)/2
t = 6 or -6 (rejected)
t = 6 s