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Gekata [30.6K]
3 years ago
9

HURRY PLZ

Physics
1 answer:
Natali [406]3 years ago
5 0

The answer correct is C:The cell is most likely prokaryotic ,but it could be eukaryotic since some unicellular are eukaryotic.


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A ski gondola is connected to the top of a hill by a steel cable of length 620 m and diameter 1.5 cm. As the gondola comes to th
xz_007 [3.2K]

Answer:

(a) 89 m/s

(b) 11000 N

Explanation:

Note that answers are given to 2 significant figures which is what we have in the values in the question.

(a) Speed is given by the ratio of distance to time. In the question, the time given was the time it took the pulse to travel the length of the cable twice. Thus, the distance travelled is twice the length of the cable.

v=\dfrac{2\times 620 \text{ m}}{14\text{ s}} = \dfrac{1240\text{ m}}{14\text{ s}}=88.571428\ldots \text{ m/s}= 89\text{ m/s}

(b) The tension, T, is given by

v =\sqrt{\dfrac{T}{\mu}}

where v is the speed, T is the tension and \mu is the mass per unit length.

Hence,

T = \mu\cdot v^{2}

To determine \mu, we need to know the mass of the cable. We use the density formula:

\rho = \dfrac{m}{V}

where m is the mass and V is the volume.

m=\rho\cdot V

If the length is denoted by l, then

\mu = \dfrac{m}{l} = \dfrac{\rho\cdot V}{l}

T = \dfrac{\rho\cdot V}{l} v^{2}

The density of steel = 8050 kg/m3

The cable is approximately a cylinder with diameter 1.5 cm and length or height of 620 m. Its volume is

V = \pi \dfrac{d^{2}}{4} l

T = \dfrac{\rho\cdot\pi d^2 l}{4l}v^2 = \dfrac{\rho\cdot\pi d^2}{4}v^2

T = \dfrac{8050\times\pi\times0.015^2}{4} \times 88.57^2

T = 11159.4186\ldots \text{ N} = 11000 \text{ N}

4 0
3 years ago
When Trinity pulls on the rope with her weight, Newton's Third Law of Motion tells us that the rope will _____
Bingel [31]

When Trinity pulls on the rope with her weight, Newton's Third Law of Motion tells us that the rope will <u>"pull back".</u>


Newton's third law of motion expresses that, at whatever point a first question applies a power on a second object, the first object encounters a power meet in extent however inverse in heading to the power that it applies.  

Newton's third law of movement reveals to us that powers dependably happen in sets, and one question can't apply a power on another without encountering a similar quality power consequently. We once in a while allude to these power matches as "action-reaction" sets, where the power applied is the activity, and the power experienced in kind is the response (despite the fact that which will be which relies upon your perspective).

6 0
3 years ago
Read 2 more answers
What is the relationship between power and voltage?
kipiarov [429]

<u>Answer:</u>

The power and voltage are related through Power Rule .

<u> Explanation : </u>

Power Rule  states  that the current I  that flows the element in the circuit  with a loss in voltage V,  then the amount of  power dissipated by that element in the circuit is the   multiplicative product of  voltage and the current.

Mathematically, power law  is

\boldsymbol{P}=\boldsymbol{I} \times \boldsymbol{V}

The rate of work done or the rate of energy consumption or production is  termed as power.Unit of power is denoted as W(watts).

Potential energy between  any two points on a circuit is called as  Voltage and is measured in volts (V) .

3 0
3 years ago
A car traveling on a flat (unbanked) circular track accelerates uniformly from rest with a tangential acceleration of 1.7 m/s^2.
Komok [63]

Answer:

The coefficient of static friction between the car and the track

u=0.572

Explanation:

We don't know the mass of the car or any other information so the acceleration is the reason to solve the friction coefficient

∑F=F_{f}=m*a_{t}

As we know

F_{f}=u*F_{N}=u*m*g

Also the center ward direction forces

F_{fc}=m*a_{c}

a_{c}=\frac{v_{t}^2}{r}

F_{fc}=m*\frac{v_{t}^2}{r}

But now vt relation with the tangential acceleration

v_{t}=2*a_{t}*\frac{\pi }{r}

replacing

F_{fc}=m*a_{t}*\frac{2\pi*r}{2r}

F_{fc}=m*a_{t}*\pi

So magnitude of the force can get by

F_{f}=\sqrt{(m*a_{t}*\pi)^{2}+(m*a_{t})^{2}}

Get the factor to simplify

F_{f}=a_{t}*m*\sqrt{(1+\pi^2)}

u*m*g=m*a_{t}*(\sqrt{1+\pi^2})

Solve to u'

u=\frac{a_{t}}{g}*(\sqrt{1+\pi^2})

u=\frac{17\frac{m}{s^2} }{9.8\frac{m}{s^2}}*(\sqrt{1+\pi^2})=0.572

5 0
3 years ago
Which two quantities can be used to describe motion? A: Displacement and weight. B: speed and acceleration. C: speed and mass. D
HACTEHA [7]
The answer is B as all the other options contain quantities not related to describing motion
3 0
2 years ago
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