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2 years ago

What are the products of the reaction with their coefficients C2H18+O2?

Chemistry

1 answer:

lozanna [386]2 years ago

4 0

Answer:

2C2H18 + 13O2 → 4CO2 + 18H2O (I balanced your equation)

Products - CO2 & H20

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Write the chemical reaction for the ammonium ion in water, whose equilibrium constant is ka. include the physical states for eac

lisabon 2012 [21]

The chemical reaction for the ammonium ion in water is:

NH4+(aq) + H2O(l) ----> H3O+ (aq) + NH3 (aq) Ka = 5.60x10^-10

The ammonium ion NH4+ in aqueous form reacts with liquid water forming hydronium ion (aqueous) and aqueous ammonia, with a Ka of 5.60x10^-10.

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2 years ago

What is the Kelvin temperature for 30°C?

Annette [7]

303.15 would be your answer

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3 years ago

I need some help with my quiz

Nezavi [6.7K]

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3 years ago

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When an ionic compound is named or its formula is written, what sort of element is placed first? What is the charge on its ions?

gizmo_the_mogwai [7]

Positive unless your mean to them then everyones negative towards you.

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3 years ago

Helium is the lightest noble gas and the second most abundant element (after hydrogen) in the universe. The mass of a helium−4 a

dmitriy555 [2]

Answer: The fraction of atom's mass contributed by nucleus is 0.99

Explanation:

Nucleons are defined as the sub-atomic particles which are present in the nucleus of an atom. Nucleons are protons and neutrons.

The isotopic symbol of Helium-4 atom is $_2^4\textrm{He}$

Number of electrons = 2

Number of protons = 2

Number of neutrons = 4 - 2 = 2

We are given:

Mass of He-4 atom = $6.64648\times 10^{-24}g$

Mass of 1 electron = $9.10939\times 10^{-28}g$

Calculating the mass contributed by the nucleus = $m_{He}-2(m_e)$

Mass of the nucleus of He-4 atom = $6.64648\times 10^{-24}-(2\times (9.10939\times 10^{-28}))=(6.64648-0.0018219)\times 10^{-24}=6.64466\times 10^{-24}$

To calculate the fraction of atom's mass contributed by the nucleus, we use the equation:

$\text{Fraction of atom's mass contributed by nucleus}=\frac{\text{Mass of nucleus}}{\text{Mass of atom}}$

Putting values in above equation, we get:

$\text{Fraction of atom's mass contributed by nucleus}=\frac{6.64466\times 10^{-24}g}{6.64648\times 10^{-24}g}=0.99$

Hence, the fraction of atom's mass contributed by nucleus is 0.99

8 0

2 years ago