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ladessa [460]
3 years ago
10

what might happen if an automobile manufacturer began making and selling cars based on a prototype that went through only one en

gineering design cycle
Physics
1 answer:
ipn [44]3 years ago
8 0
One engineering design cycle will have these problems:
1. Reliability testing will not be enough to manufacture a robust, reliable product.
2. Many design and manufacturing flaws may not be detected.
3. Cost optimization will be poor.
4. Customer satisfaction will be low.
5. There will be several product recalls to fix problems due to design and manufacturing deficiencies.
6. The product will eventually be withdrawn.


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Complete the statement below with the correct term.
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Calculate the centripetal force on the end of a 100 m (radius) wind turbine blade that is rotating at 0.5 rev/s. Assume the mass
Alja [10]

Answer:

3947.6 N

Explanation:

Centripetal Force: This is the force that tend to moves a body towards the center of a circle during circular motion.

The formula for centripetal force is

F = mω²r ........................ Equation 1

Where F = Centripetal force, ω = angular velocity, r = radius.

Where π = 3.1415

Given: m = 4 kg, ω = 0.5 rev/s = (0.5×2π) rad/s = 3.1415 rad/s, r = 100 m.

Substitute into equation 1

F = 4(3.1415)²(100)

F = 3947.6 N

Hence the centripetal force on the turbine blade = 3947.6 N

6 0
3 years ago
The measurement of 50m east is
Nostrana [21]

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6 0
4 years ago
When a board with a box on it is slowly tilted to a larger and larger angle, common experience shows that the box will at some p
Savatey [412]

Answer:

c. The coefficient of kinetic friction is less than the coefficient of static friction

Explanation:

When the box finally does break loose. Then the component of the box weight which is parallel to the board weight parallel component, is equal to the \mu_gn.

w_{box}=\mu_gn

For the box to acce;erate thee must be non-zero net force acting on the box parallel to the board. Or we can say,

w_1>f_g\\w_1>\mu_gn

Therefore the force of kinetic friction must be less than the force of static friction. Thus,

\mu_g

3 0
3 years ago
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