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Kitty [74]
3 years ago
15

What is the velocity in meters per second of a runner who runs exactly 110 m toward the beah in 72 seconds?

Physics
2 answers:
rjkz [21]3 years ago
8 0
B) 1.53 m/s towards the beach
Vitek1552 [10]3 years ago
6 0

Answer:

B). 1.53 m/s toward the beach

Explanation:

Velocity consists of a) a magnitude (the speed) and b) a direction.

The speed is given by the ratio between the distance covered and the time taken:

v=\frac{110 m}{72 s}=1.53 m/s

while the direction is given in the problem, it is the same as the displacement (toward the beach).

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Answer:

0.006075Joules

Explanation:

The final kinetic energy of the system is expressed as;

KE = 1/2(m1+m2)v²

m1 and m2 are the masses of the two bodies

v is the final velocity of the bodies after collision

get the final velocity using the law of conservation of momentum

m1u1 + m2u2 = (m1+m2)v

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0.054 = 0.24v

v = 0.054/0.24

v = 0.225m/s

Get the final kinetic energy;

KE = 1/2(m1+m2)v

KE = 1/2(0.12+0.12)(0.225)²

KE = 1/2(0.24)(0.050625)

KE = 0.12*0.050625

KE = 0.006075Joules

Hence the final kinetic energy of the system is 0.006075Joules

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2 years ago
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A massless string connects a 10.00 kg mass to a 13.00 kg cart which is resting on a frictionless horizontal surface. The mass ha
ch4aika [34]

The cart's acceleration to the right after the mass is released  is determined as 7.54 m/s².

<h3>Acceleration of the cart</h3>

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Thus, the cart's acceleration to the right after the mass is released  is determined as 7.54 m/s².

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oxygen is used up is the answer

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