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Kitty [74]
4 years ago
15

What is the velocity in meters per second of a runner who runs exactly 110 m toward the beah in 72 seconds?

Physics
2 answers:
rjkz [21]4 years ago
8 0
B) 1.53 m/s towards the beach
Vitek1552 [10]4 years ago
6 0

Answer:

B). 1.53 m/s toward the beach

Explanation:

Velocity consists of a) a magnitude (the speed) and b) a direction.

The speed is given by the ratio between the distance covered and the time taken:

v=\frac{110 m}{72 s}=1.53 m/s

while the direction is given in the problem, it is the same as the displacement (toward the beach).

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Why are common measurement systems important
kenny6666 [7]
So that international people don't mistake units for others. ex 1 inch could be mistaken for 1 cm in non American countries
6 0
3 years ago
Water moves to the top of tall trees because of _____.
abruzzese [7]

Hello!

Answer-  Capillary action and evaporation. It's not just the capillary action, but the pull from transpiration (the evaporation of water from the tree) that is used to pull water up from the roots. This is why the correct answer is option C) capillary action and evaporation.

Hope this helps! Have a great day,

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7 0
4 years ago
Diffraction of sound waves is demonstrated when sound waves with a frequency of 1300 Hz from a distant source are diffracted thr
Tresset [83]

Answer:

39.05°

Explanation:

As we know that, the diffraction is the phenomena of bending of light when it passes through  an obstacle.

Mathematically,

dsin\theta=n\lambda

Here, d is slit width, \lambda is the wavelength, n is the order, \theta is the angle.

Given that, d is 84 cm, n is 2, and the wavelength can be calculated as,

\lambda=\frac{c}{f}

Here, c is the speed of sound and f is the frequency of sound wave.

Here, c is 343 m/s and f is 1300 Hz,

Therefore,

\lambda=\frac{343 m/s}{1300 Hz}\\\lambda=0.264m

Recall diffraction equation in term of sin\theta.

sin\theta=\frac{n\lambda}{d}

Put all the variables.

sin\theta=\frac{2\times 0.264 m}{84 cm}\\sin\theta=\frac{2\times 0.264 m}{0.84 m}\\\theta=39.05^{\circ}

Therefore, it is the required angle between the first 2 order of diffraction.

3 0
3 years ago
If the half-life of a 2.0 gram sample of a radionuclide is 15 hours, then the half-life of a 1.0 gram sample of the same radionu
Lerok [7]

7.5 hours or 450 minutes. 15/2=7.5

5 0
3 years ago
PLZ hurry! Thank you
Alenkinab [10]

Answer:do it again

Explanation:

It will work

3 0
3 years ago
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