Question

At a certain temperature, the rate constant for this reaction is 5.64×10−4 s−1 . Calculate the half-life of cyclopropane at this temperature.

Answer 1

Answer:

$t_{1/2}= 20.47\ minute$

Explanation:

given,

constant rate for the reaction(k) =  5.64  ×  10⁻⁴ s⁻¹

to calculate the half life  = ?

$t_{1/2} = \dfrac{0.693}{k}$

$t_{1/2} = \dfrac{0.693}{5.64\times 10^{-4}}$

on solving the above equation

$t_{1/2} = 1228.72 s$

$t_{1/2} = \dfrac{1228.72}{60}$

$t_{1/2}= 20.47\ minute$

hence, the half-life of cyclopropane at this temperature =$t_{1/2}= 20.47\ minute$