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lisabon 2012 [21]
2 years ago
12

At a certain temperature, the rate constant for this reaction is 5.64×10−4 s−1 . Calculate the half-life of cyclopropane at this

temperature.
Physics
1 answer:
oee [108]2 years ago
5 0

Answer:

t_{1/2}= 20.47\ minute

Explanation:

given,

constant rate for the reaction(k) =  5.64  ×  10⁻⁴ s⁻¹

to calculate the half life  = ?

t_{1/2} = \dfrac{0.693}{k}

t_{1/2} = \dfrac{0.693}{5.64\times 10^{-4}}

on solving the above equation

t_{1/2} = 1228.72 s

t_{1/2} = \dfrac{1228.72}{60}

t_{1/2}= 20.47\ minute

hence, the half-life of cyclopropane at this temperature =t_{1/2}= 20.47\ minute

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