You are given the mass of the book with an initial
height of 0.77m. You are also given the final height of the book, 2m above the
floor. The problem requires you to find the work done on the book. It is said
that work is equal to force times distance. And that force is equal to mass
times acceleration due to gravity.
W=Fd
W=mgd=mgh
W=(1.7kg)(9.8m/s^2)(2m-0.77m)
W=20.49J
<span>The work is equal to 20.49J.</span>
Answer:
C
Explanation:
Gram negative is most likely to be oxidase positive.
6 molecules of carbon dioxide
1 molecule of sugar produced
6 carbon atoms on the left
6 carbon atoms on the right
made up of more than one cell.
Answer:
The force per unit length (N/m) on the top wire is 16.842 N/m
Explanation:
Given;
distance between the two parallel wire, d = 38 cm = 0.38 m
current in the first wire, I₁ = 4.0 kA
current in the second wire, I₂ = 8.0 kA
Force per unit length, between two parallel wires is given as;

where;
μ₀ is constant = 4π x 10⁻⁷ T.m/A
Substitute the given values in the above equation and calculate the force per unit length

Therefore, the force per unit length (N/m) on the top wire is 16.842 N/m